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Degger [83]
3 years ago
10

Please help me ASAP

Chemistry
1 answer:
blondinia [14]3 years ago
4 0

Answer:

weak acid

Explanation:

pH scale is from 0 to 14

pH =7 is for water which is neutral.  it is neither acidic or basic as the hydrogen ion concentration is equal to hydroxyl ion concentration.

Lesser the pH value than 7 greater the acidic nature. And greater the pH value  than 7 more the basic nature.

Given pH=3-7 So the indicated interval represents weakly acidic.

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____H3PO4 + ____ KOH --> ______K3PO4 + ____H2O can someone please balance that chemical equation?
Murrr4er [49]

Answer:

H3PO4 + 3KOH ----> K3PO4 + 3H2O

Explanation:

The valency of K element is + 1 while that of PO4 compound is -3

Hence, at least 3 K atoms are needed to combine with PO4 to form K3PO4 compound.

Hence, the revised equation will be

H3PO4 + 3KOH ----> K3PO4 + 3H2O

Now, the number of atoms and charges of each element is a given equation are equal on both the left and right hand side.

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Chemistry balance equations C2H +O2=CO2+H2O​
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7 0
2 years ago
Several general characteristics of metabolic reactions or reaction pathways are listed below. sort them into the appropriate met
Kobotan [32]
Answers are:
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8 0
3 years ago
Read 2 more answers
1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percen
Naddik [55]

Answer:

72.8 % (But verify explanation).

Explanation:

Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL

Used concentration of NaOH= 1.5M

Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol

Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g

% of acetic acid in vinegar=8.64 %

% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %

Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

8 0
3 years ago
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