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horrorfan [7]
3 years ago
10

Which of the following metal atoms would have the highest conductivity?

Chemistry
2 answers:
Alex17521 [72]3 years ago
8 0

Answer: Option (d) is the correct answer.

Explanation:

A metal which has the largest size and the most valence electrons would have the highest conductivity because the larger is the size of a metal the more freely electrons can move in it. Hence, the metal can conduct electricity.

If the atom is smaller in size then the electrons will be tightly held around the nucleus and hence they won't be able to move freely. Therefore, they will not conduct electricity.

Thus, we can conclude that the atom with the largest radius and the most valence electrons would have the highest conductivity.

Harlamova29_29 [7]3 years ago
3 0

Answer:

D. the atom with the largest radius and the most valence electrons

Explanation:

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Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
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Combustion analysis is performed on 0.50 g of a hydrocarbon, and 1.47 g of CO2 and 0.902 g of H2O are produced. What is the empi
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1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>
  • Mass of CO₂ = 1.47 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>
  • Mass of compound = 0.5 g
  • Mass of C = 0.4 g
  • Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>
  • C = 0.4 g
  • H = 0.1 g
  • Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>
  • Empirical formula = CH₃
  • Molar mass = 30 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

4 0
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