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densk [106]
3 years ago
14

12,14 and 16 are the length of the sides on the triangle

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0

Answer: 81.33 square units


Step-by-step explanation:

Given sides of triangle = 12,14 and 16 are the a,b and c respectively.

Thus the perimeter of triangle =a+b+c=12+14+16=42

The semi perimeter of triangle s=\frac{42}{2}=21

By Heron's formula

Area of triangle = \sqrt{s(s-a)(s-b)(s-c)}

=\sqrt{21(21-12)(21-14)(21-16)}\\\\=\sqrt{21(9)(7)(5)}\\\\=\sqrt{6615}\\=81.3326\approx81.33\text{ square units}

The area of triangle =81.33 square units.

velikii [3]3 years ago
5 0
The answer is B)81.33 square units
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_____

<em>Additional comment</em>

The "triangle" cannot exist, as the side lengths are shown as 8, 12, and 35. The long side is too long. Nice math; bad geometry.

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