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densk [106]
3 years ago
14

12,14 and 16 are the length of the sides on the triangle

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0

Answer: 81.33 square units


Step-by-step explanation:

Given sides of triangle = 12,14 and 16 are the a,b and c respectively.

Thus the perimeter of triangle =a+b+c=12+14+16=42

The semi perimeter of triangle s=\frac{42}{2}=21

By Heron's formula

Area of triangle = \sqrt{s(s-a)(s-b)(s-c)}

=\sqrt{21(21-12)(21-14)(21-16)}\\\\=\sqrt{21(9)(7)(5)}\\\\=\sqrt{6615}\\=81.3326\approx81.33\text{ square units}

The area of triangle =81.33 square units.

velikii [3]3 years ago
5 0
The answer is B)81.33 square units
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klemol [59]

7/10 as hundredths decimal: .07

7/10 as fraction: 7/100

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3 years ago
I need help I don’t remember these
Levart [38]

4. Using the given formula, replace t with 8 seconds and multiply:

343 x 8 = 2,744 meters.

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6 0
3 years ago
The average temperature of the week is 80 degrees. The first 3 days have an average of 78 and the average of the last 3 days is
Tju [1.3M]

Answer:

80

Step-by-step explanation:Solution:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The given numbers are 78 & 80

step 2 Find the sum of the given two numbers.

sum = 78 + 80 = 158

step 3 Divide the sum by 2 to get the average.

average = 158/2

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3 0
3 years ago
50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n
irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0
3 years ago
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Ratling [72]

Answer:

123

Step-by-step explanation:

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7 0
3 years ago
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