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In-s [12.5K]
3 years ago
8

Guess the rule and add the next number in the sequence. 7, 10, 16, 25, 37,

Mathematics
1 answer:
Delvig [45]3 years ago
4 0

Answer:

Step-by-step explanation:

Let us first closely examine the sequence for any mathematical correlation between the terms of sequence.

It is visualized that the series is progressing with addition of increasing even numbers starting with +6 ( +6, +8, +10, +12, +14, +16, +18 …) in the previous term to obtain next terms of the series. This logic continues for entire series.

The given series is:

1 ,7 ,15 ,25 ,37

Starting with first number of the series

1

1 + 6 = 7

7 + 8 = 15

15 + 10 = 25

25 + 12 = 37

37 + 14 = 51

51 + 16 = 67

67 + 18 = 85

The extended series is

1, 7, 15, 25, 37, 51, 67, 85

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56.27 in expanded form​
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Answer:

Step-by-step explanation:

 56.27 =

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+ 6 × 1  

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Expanded Exponential Form:

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Word Form:

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5 0
2 years ago
Explain how you know 7/12 is greater than 1/3 but less than 2/3
Roman55 [17]
7/12
1/3=4/12
2/3=8/12

7/12>1/3
<span>7/12<2/3
</span>

convert all of these to a common denominator:
7/12 , 1/3 , 2/3
---
7/12 = 7/12
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---
place into compound inequality:
---
(1/3=4/12) < (7/12=7/12) < (2/3=8/12)


3 0
3 years ago
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"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

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Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

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So

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(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

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