F(x) = 2x - 1
subtitute x = 0 to the equation:
f(0) = 2· 0 -1 = 0 - 1 = -1
f(0) = -1
Substitute x into the second equation:
3(6y-11)-2y=-1
18y-33-2y=-1
16y=32
y=2
Then put the y value into the first equation to get x:
x=6(2)-11
x=1
There you go!
Please mark brainliest
Answer:
No it is not a solution to 6u-1<-19
Answer:
As per the question, we need to convert product of sum into sum of product,
Given:
(A' +B+C')(A'+C'+D)(B'+D'),
At first, we will solve to parenthesis,
= (A'+C'+BD) (B'+D')
As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,
(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)
Now,
= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"
As we know that AA' = 0, it mean
=A'B'+A'D'+C'B'+C'D'+D*0+B0
=A'B'+A'D'+C'B'+C'D' as B * 0 and D*0 = 0
Finally, minimum sum of product boolean expression is
A''B'+A'D'+C'B'+C'D'
=
No ffffffffffffffffffffffffffffffff
