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Slav-nsk [51]
3 years ago
6

C=a/5t what does t equal?

Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0
Photo has the answer! hope it helped

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Find the indicated one-sided limit, if it exists:
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The main point which will immediately make it clear is that you have to plug in 2 for x so that you can find the linit. So, using this simple method you will get the <span>-1/4 answer. Hope you will agree with me and find this useful! Regards.</span>
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Which of the following pairs of functions are inverses of each other?
aliina [53]
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A or C

Step by Step Explanation:

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Read 2 more answers
Which equations show the zero property of multiplication? Choose exactly two answers that are correct. A. –4.7 • 0 = 0 B. –8 + 8
tester [92]
The zero property is anything multiplied zero to equal zero

Answers: A and D

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6 0
3 years ago
Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar
xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ_{e}^2 → S_{e} ^{2}), you have to use the following formula:

Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>

                        n₁+n₂+n₃-k

Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u>  915.8   </u>  = 16.067

                 20+20+20-3                  57

DfE= N-k = 60-3= 57

3. To calculate the value of the statistic you have to divide the MSB by MSE

F= \frac{Mean square B}{Mean square E} = \frac{5.32}{16.067} = 0.33

4. P(F_{2; 57} ≤ F) = P(F_{2; 57} ≤ 0.33) = 0.28

I hope you have a SUPER day!

3 0
3 years ago
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