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3 years ago

Find the area of each figure. use 3.14 for pi

Mathematics

1 answer:

Dvinal [7]3 years ago

4 0

Answer:

1) 39.5 ft^2

1) 139.15m^2

Step-by-step explanation:

2) area of a rectangle formula : LW

Area of a triangle:(bh)/2

Area of a semi circle:( Pi*r^2)/2

Area of a square: S^2

Area of figure one:

Lw+(b1*h1)/2+(b2*h2)/2

8*4+(2*3)/2+(3*3)/2

32+3+4.5=39.5

Area of fig 2:

S^2+(pi*r^2)/2

10^2+(3.14*5^2)/2

100+78.5/2

100+39.25=139.25

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Solve each quadratic equation. Show your work. 4x^2=100

ZanzabumX [31]

Hello there!

4x² = 100

We wanna start by dividing both sides by 4

4x²/4 = 100/4

x² = 25

Now we can take square root

x = +/-√25

x = 5 or x = -5

As always, it is my pleasure to help students like you!

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3 years ago

To participate in a baseball league, the required equipment for each player is a glove, a hat, and a pair of cleats. A glove cos

Leona [35]

Answer:

1222.2

explanation:

53.95 x 12 = 647.40

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29.95 x 12 = 359.40

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6 0

3 years ago

Which of these expressions is equivalent to 3x(x-1)-5(x-1)? Select all that apply.

Maru [420]

Answer:

3x(x-1)-5(x-1)

=3x²-3x-5x+5 (we can count it one by one)

=3x²-8x+5 (we can calculate the same variable)

#i'm from indonesia

hope it helps.

6 0

3 years ago

Read 2 more answers

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2$

3 0

3 years ago

I'll mark brainliest Please help

Ilia_Sergeevich [38]

Answer:

Y=0.1(1.25)^t is growth. Y=426(0.98)^t is decay. Y=100(1-1/2)^t is decay. Y=((1-0.03) 1/2) ^2t is decay. And y=2050(1/2)^t is decay. Hope this helps!

Step-by-step explanation:

5 0

3 years ago