Ask question

Ask question

All categories

3 years ago

12

Write the following comparison as a ratio reduced to lowest terms. 88 quarters to 30 dollars

1 answer:

LUCKY_DIMON [66]3 years ago

6 0

You need to find common factors. The factors of 88 are 1 and 88, 2 and 44, 4 and 22, and 8 and 11. The factors of thirty are 1 and 30, 2 and 15, and 5 and 6. The greatest common factor is 2 so the ratio is 44:15.

You might be interested in

Joshua owns a trucking company. For every truck that goes out, Joshua must pay the driver $25 per hour of driving and also has a

lara [203]

Answer:

number of miles=a

number of hours=y

Step-by-step explanation:

<h3>$25 per how y of driving</h3><h3>$2 per how many a per mile</h3><h3>a x y = the total price </h3><h3 /><h3 /><h3 /><h3>plz mark me as the brainliest </h3>

6 0

2 years ago

Help ASAP please!

Iteru [2.4K]

Answer:A

Step-by-step explanation:

it is A

6 0

3 years ago

Read 2 more answers

Ye has his own business. He checks his sales receipts three times a day, his afternoon sales were 50$ more than his mourning sal

IRINA_888 [86]

Answer:

The answer is 150

Step-by-step explanation:

It's 150 because ye evening sales are three times of his afternoon sales.

SO that means you have to times 50x3=150 or you can add 50+50+50=150. there is your answer.

3 0

3 years ago

Read 2 more answers

Paula tiene una cartulina de 50x65 cm. Quiere hacer 5 rectángulos de 210x297 mm. ¿Tendrá suficiente con una cartulina?

brilliants [131]

Answer:

?????????????????????????

3 0

2 years ago

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago