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Arturiano [62]
3 years ago
11

A new bank account is opened on week 1 with a $200 deposit. After that first week, weekly deposits of $55 are made in the accoun

t. If y represents the total deposited into the account and x represents the number of weeks, which function rule describes this situation?
Mathematics
2 answers:
inysia [295]3 years ago
7 0
Y=55x+200, you multiply the number of weeks by the amount of money, and add 200 because they started with that.   
Nina [5.8K]3 years ago
5 0

Answer: y = 200+ 55x

Step-by-step explanation:

Hi, to answer this question we have to write an equation using the information given:

So, the total deposits (y) are equal to the week 1 deposit (200) plus the product of the amount of the deposits per week (55) and the number of weeks (x).

Mathematically speaking:

y = 200+ 55x

Feel free to ask for more if needed or if you did not understand something.

You might be interested in
Jeri's lawn service charges an initial fee of $4.50 plus $3 an hour. If she is asked to
STALIN [3.7K]

Answer:

5 hours 22 minutes

Step-by-step explanation:

Let us represent the number of hours that Jeri worked as: h

Jeri's lawn service charges an initial fee of $4.50 plus $3 an hour

= $4.50 + $3 × h

= $4.50 + 3h

If she is asked to start before 7 a.m. Jeri charges 1.5 times the regular amount.

= 1.5 × ($4.50 + 3h)

If she made $29.25 on a job that began at 5 am, how many hours did Jeri work?

Hence, we have the final equation;

= 1.5 × ($4.50 + 3h) = $29.25

= 6.75 + 4.5h = 29.25

Collect like terms

= 4.5h = 29.25 - 6.75

4.5h = 22.5

h = 22.5/4.5

h = 5.3571428571

Approximately= 5.36 hours

1 hour = 60 minutes

0.36 hour =

60 × 0.36

= 21.6 minutes

Approximately ≈ 22 minutes

Therefore, Jeri worked for 5 hours 22 minutes

7 0
3 years ago
A piece of metal has a mass of 2210 g. The volume of the metal is 260 cm³.
Vlada [557]

Answer:

density= 8.5\,\,\frac{g}{cm^3}

Step-by-step explanation:

Recall that the formula for density is:

density=\frac{mass}{volume}

therefore for this case we have:

density=\frac{mass}{volume} \\density=\frac{2210}{260} \,\frac{g}{cm^3} \\density= 8.5\,\,\frac{g}{cm^3}

6 0
4 years ago
Read 2 more answers
HELP PLEASE! and give out good answers.
zhuklara [117]
I think its A. There is a peak in the orders from 6 to 10 pounds
7 0
3 years ago
The product of two consecutive positive integers is 132. What are the integers?
alina1380 [7]

Answer:

The integers are 11 and 12

Step-by-step explanation:

11 and 12 are consecutive positive integers, and 11 x 12 = 132.

5 0
3 years ago
At a new exhibit in the Museum of Science, people are asked to choose between 94 or 220 random draws from a machine. The machine
Tresset [83]

Answer:

0.0869 = 8.69% probability of getting more than 61% green balls.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The machine is known to have 99 green balls and 78 red balls.

This means that p = \frac{99}{99+78} = 0.5593

Mean and standard deviation:

\mu = p = 0.5593

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5593*0.4407}{99+78}} = 0.0373

a. Calculate the probability of getting more than 61% green balls.

This is 1 subtracted by the pvalue of Z when X = 0.61. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.61 - 0.5593}{0.0373}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131

1 - 0.9131 = 0.0869

0.0869 = 8.69% probability of getting more than 61% green balls.

8 0
3 years ago
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