To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
Answer:
9 1/4
Step-by-step explanation:
1/2 = 2/4
11 1/2 = 11 2/4
11 2/4 - 2 1/4
11 - 2 = 9
2/4 - 1/4 = 1/4
9 1/4
Answer:
You can not write an equation then because it would just be a vertical line, ex: x=4 or x=-4. I hope this helps!
Step-by-step explanation:
W^-3
(4)^-3 = 1/(4)^3
1/64.
The solution is 1/64.
Answer:
26units!
Step-by-step explanation:
