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grigory [225]
3 years ago
9

there are a 160 boys and girls playing in the soccer tournament 32 of the students are wearing orange what percentage of the pla

yers are wearing orange
Mathematics
2 answers:
madreJ [45]3 years ago
3 0

Answer:

the ansrew is 3%

Step-by-step explanation:

160 divided by 32= 3% mostly around 3.3125 i am not 100% sure so u should probably wait for someone else but this is my way of seeing the problem.

Harrizon [31]3 years ago
3 0
<h3>Answer:</h3><h3>3% of them are wearing orange</h3>

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I need help please 36 points
geniusboy [140]

Using the power of zero property, we find that:

a) The simplification of the given expression is 1.

b) Since , equivalent expressions are:  and .

--------------------------------

The power of zero property states that any number that is not zero elevated to zero is 1, that is:

Thus, at item a, , thus the simplification is .

At item b, equivalent expressions are found elevating non-zero numbers to 0, thus  and .

5 0
2 years ago
What is the equation has intercepts at x(1, 0, 0), y(0, -1,0), and z(0, 0, 2)
bulgar [2K]

In intercept form, the plane that has these intercepts is ...

... x/(x-intercept) + y/(y-intercept) + z/(z-intercept) = 1

... x/1 + y/(-1) + z/2 = 1

... 2x -2y +z = 2 . . . . . in standard form

3 0
3 years ago
The difference between 8 and a number is 5.
pav-90 [236]

Answer:

the answer is 3.

Step-by-step explanation:

Difference between means to subtract.

8 - 5 = 3

3 0
2 years ago
Read 2 more answers
One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
Read 2 more answers
Nicholas wrote the steps below to
Inessa05 [86]

Answer:

He does not divide the numerator and the denominator by the same number. Nicholas divides 20 by 5 and 30 by 6. He ought to have divided 30 by 5 as well and then simplified.

P.S. Nicholas should have just divided both 20 and 30 by 10 to simplify in one step

7 0
2 years ago
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