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3 years ago

Quick Help please? :D

Mathematics

1 answer:

Vikentia [17]3 years ago

4 0

I would say B; trapezoid. That is what it appears as.

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Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

21. Which number below is equivalent to 3.82 x 10-5?

IceJOKER [234]

Answer:

19.10

Step-by-step explanation:

If im correct,

You subtract 10 and 5. Wich is 5. Then multiply that by 3.82.

3 0

3 years ago

Use unit rate to find the unknown value: 2/8 = 7/? <br> 1. 56<br> 2. 4<br> 3. 28<br> 4. 24

bezimeni [28]

Answer:

I believe the awnser is 3

4 0

2 years ago

Can someone please help me solve these two quadratic equations by factoring!

snow_tiger [21]

Answer:

1st one: (x-2)(x+10)

2nd one: (x-7)(x-3)

Step-by-step explanation:

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2 years ago

Find the value of cos C rounded to the nearest hundredth, if necessary

Sindrei [870]

$\bold{\frac{5}{13} or 0.38}$

Answer:

Solution given:

here

by using Pythagoras law

hypotenuse =

$\displaystyle\sqrt{adjacent ²+opposite ²}\\=\sqrt{15²+36²}=39$

Cos C= $\frac{adjacent} {hypotenuse}=\frac{15}{39}=\frac{5}{13} or{0.38}$

6 0

2 years ago