$y=2\sqrt[3]{x+2}\ \ \ |divide\ both\ sides\ by\ 2\\\\\sqrt[3]{x+2}=\dfrac{y}{2}\to x+2=\left(\frac{y}{2}\right)^3\ \ \ |subtract\ 2\ from\ both\ sides\\\\x=\dfrac{y^3}{2^3}-2\\\\x=\dfrac{1}{8}y^3-2\\\\\boxed{f(x)=2\sqrt[3]{x+2}\to f^{-1}(x)=\frac{1}{8}y^3-2}$

5 0

3 years ago

PLEASE EMERGENCY!!!!<br> Which of the following statements is FALSE?

Ivahew [28]

Answer:

Third one.

BO is not 7.8 cm

Step-by-step explanation:

3 0

3 years ago

Classify the quadrilateral.

Sedbober [7]

Answer: B

Step-by-step explanation: If a quadrilateral is a parallelogram, then opposite sides are congruent and parallel, so this must be a parallelogram.

4 0

3 years ago