45 is the answer. It is the least common multiple of 5 and 9. Multiples of 5: 5, 10,15,20,25, 30, 35, 40, 45 and multiples of 9: 9, 18, 27, 36, 45
Hello!
You put 16 in for u and 4 in for t
v = (16) + 10(4)
Multiply
v = 16 + 40
Add
v = 56
The answer is v = 56
Hope this helps!
Answer:
12.54
Step-by-step explanation:
5>0
Answer: a6=70
Step-by-step explanation:
we know that
In the Arithmetic Sequence the formula is:
an= a1 + d(n−1)
where
a1 is the first term
d is the common difference
n is the number of terms
in this problem
a1=5
a2=18
a3=31
a4=44
a5=57
so
d=a2-a1 or a3-a2 or a4-a3 or a5-a4
d=57-44----> 13
find a6
a6= a1 + d(n−1)
n=6
d=13
a1=5
a6=5+13*(6-1)----> a6=5+13*5----> a6=70