3 years ago

Find the equation of the line with a slope of 3/4 that goes through the point (8,10)

Mathematics

2 answers:

GenaCL600 [577]3 years ago

7 0

the answer is ......... y=3/4+10

Reika [66]3 years ago

4 0

This is good.

Using the general format: y -y1 = m(x-x1), format of a slope and a point.

(x1, y1) = (8,10)

y -10 = (3/4)*(x-8)
y -10 = 3x/4 -6 Multiply through by 4.
4y -40 = 3x -24
4y = 3x -24 + 40
4y = 3x + 16.

So equation of the line is: 4y = 3x + 16.

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olga nikolaevna [1]

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Step-by-step explanation:

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2 years ago

QuestionIn PQR, sin P = 1/3, sin R = 2/3,and p = 9. Find the side length r.

mamaluj [8]

Lets draw our triangle:

Lets use the "Law of Sines" to find our side r:

$\frac{p}{\sin P}=\frac{r}{\sin R}\rightarrow\frac{9}{\frac{1}{3}}=\frac{r}{\frac{2}{3}}\rightarrow9\times\frac{3}{1}\times\frac{2}{3}=r\rightarrow r=18$

So r=18