Write a real world problem for 5n+8=43

What is the distance between A(-8, 4) and B(4, -1)?

Anettt [7]

Answer:

The distance between A(-8, 4) and B(4, -1) is 13 units.

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula given by:

$\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (x₁, y₁) and let B(4, -1) be (x₂, y₂). Substitute:

$d=\sqrt{(4-(-8))^2+(-1-4)^2}$

Evaluate:

$d=\sqrt{(12)^2+(-5)^2}$

So:

$d=\sqrt{144+25}=\sqrt{169}=13\text{ units}$

The distance between A(-8, 4) and B(4, -1) is 13 units.

7 0

3 years ago

Read 2 more answers

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

Give work for equations following: -x+2y<-4 2x+3y>6 thanks sooooo much!!!!

Schach [20]

Answer: See below

Step-by-step explanation:

A) $-x+2y < -4$

$-x+2y-2y < -4-2y$

$-x < -4-2y$

Multiply both sides by -1 and reverse the inequality:

$\left(-x\right)\left(-1\right) > -4\left(-1\right)-2y\left(-1\right)$

$x > 4+2y$

B) $2x+3y > 6$

$2x+3y-3y > 6-3y$

$2x > 6-3y$

$\frac{2x}{2} > \frac{6}{2}-\frac{3y}{2}$

$x > \frac{6-3y}{2}\\x > 3-\frac{3y}{2}$

3 0

3 years ago

Can someone help me on problems 9, 10 and 11 please!!!

Rasek [7]

9. You shouldn't agree, because they are equal to one another.

10. 84 cents plus 61 should be $1.45 because 84 + 61 is 145 and 100 cents equals 1 dollar, and then you have 45 left over.

100 - .63 is .37 because the whole painting is equal to 1, or .1, or in this case I used it as 100. The drawing is up to you, but you can just draw a canvas and shade in a little bit more than half but not the full canvas. .37 of the canvas is left.

7 0

4 years ago

Read 2 more answers

When shooting free throws, David is successful 7 out of every 10 shots.if he attempts 100 free throws ,about how many times will

ira [324]

100 free throws* (7 goals/ 10 free throws)= 70 goals.

If David attempts 100 free throws, he will be successful about 70 times~

7 0

4 years ago