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soldier1979 [14.2K]
3 years ago
13

PLEASE HELP ME IM NEW TO THIS PROGRAM AND I DONT KNOW HOW TO DO THIS

Mathematics
1 answer:
Elenna [48]3 years ago
3 0
First in the right one; second in the left one; third in the right one; fourth in the left one; fifth in the right one
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Find the sum of the first 30 terms of the sequence below. an=4n+1
dmitriy555 [2]
That would be 1,890.
6 0
3 years ago
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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
Find the volume of the following compound shape.<br>​
Bess [88]
<h3>Given:</h3>
  • Cone
  • Cylinder
<h3>Volume of the cone:</h3>

v =  \frac{1}{3} \pi {r}^{2} h

v =  \frac{1}{3}  \times \pi \times  {10}^{2}  \times 10

v = 1047.20 \:  {cm}^{3}

<h3>Volume of the cylinder:</h3>

v = \pi {r}^{2} h

v = \pi \times  {10}^{2}  \times 10

v = 3141.59 \:  {cm}^{3}

<h3>Total volume:</h3>

v = 1047.20 + 3141.59

v = 4188.79 \:  {cm}^{3}

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>4188.7</u><u>9</u><u> </u><u>cubic</u><u> </u><u>centimeters</u><u>.</u>

5 0
2 years ago
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I need help I'm so confused
borishaifa [10]
A = L x W = 8 x 17 = 136
answer
C. 136 sq. units
8 0
3 years ago
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I know the answer is 60 but how would I put it in words
saul85 [17]
it would be 60 then u find the factors to get to 60 and then after u find the factors that would be ur answer then u put sixty is the Lcm 
8 0
3 years ago
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