$\dfrac{1}{3}+d=\dfrac{5}{6}\qquad|-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1\cdot2}{3\cdot2}\\\\d=\dfrac{5}{6}-\dfrac{2}{6}\\\\d=\dfrac{5-2}{6}\\\\d=\dfrac{3}{6}\\\\d=\dfrac{3:3}{6:3}\\\\\boxed{d=\dfrac{1}{2}}$

7 0

2 years ago

The sides of an equilateral triangle measure 16 inches. The midpoints of the sides of the triangle are joined to form another eq

Alex Ar [27]

Answer:

90 inches

Step-by-step explanation:

The perimeter of the inscribed triangle is 1/2 that of the enclosing triangle. So, the total of perimeters is ...

(3·16 in)(1 +1/2 +1/4 +1/8) = (48 in)(15/8) = 90 inches

5 0

2 years ago

A 56 yard loss in football game

o-na [289]

56 yard loss is -56yds

4 0

3 years ago