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olganol [36]
3 years ago
15

In a couple of sentences and in your own words describe in what ways horizontal, vertical, and oblique asymptotes can be identif

ied.
Mathematics
1 answer:
drek231 [11]3 years ago
5 0
A horizontal asymptote is one in which y has a limit as x approaches positive or negative infinite. It is usually due to both the denominator and the numerator having the same highest degree term, and the coefficient created by their proportion serves as the asymptote. For example, (2x^2 + 1) / (3x^2) would have a horizontal asymptote of 2/3

A vertical asymptote is an x value at which y approaches infinite. One example includes when the denominator of the function approaches zero at a certain point. For example, (x^2 + 3) / (x + 1) has a vertical asymptote at x=-1, since the denominator approaches zero as x approaches this point. 

For an oblique asymptote, y generally takes the form of a linear function as x approaches infinite. This is the case when the highest term in numerator is one degree higher than the highest degree term in the denominator. 

Examples include (5x^2 + 2) over 2x, where the oblique asymptote is (5/2)x, and even the linear function 2x+3 has an oblique asymptote of 2x
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Answer:

B = 14pi

Step-by-step explanation:

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Algebra 1 please help! super easy
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Read 2 more answers
Could someone help me with this?
natulia [17]
Distributive property was the first property used in STEP 1, where -4 was distributed to -3x+ 2 resulting in the equation in STEP 1. Next in STEP 2, commutative property of addition no matter how 12x and 6x are arranged, when you add them together the result will be the same. 
*Take note that 12x and 6x are put together because they are like terms. 

For Steps 3 and 4, you will see that the addition property of equality was used in STEP 3. To keep the equation equal, you will add the same number on both sides.

STEP 4 uses Division property of Equality. Like Step 3, to keep both sides of the equation equal, you must divide both sides with the same number. It keeps the statement true by doing so. 

STEP 4 and 5 uses transitive property if you examine both as a whole. 
Transitive property assumes that if a = b and b = c, then a = c

If   18/18 (a) = 1 (b),  and x (c) = 18/18(a)  then, x (c) = 1 (b). 
5 0
3 years ago
10.
vodomira [7]
<h3>Solution:</h3>
  • Given, side (a) = x+3
  • We know, surface area of a cube = 6a^2
  • Therefore, the surface area of the cube
<h3> </h3><h3>6(x + 3) ^{2}  \\  = 6( {x}^{2}  + 6x + 9) \\  = 6 {x}^{2}  + 36x + 54</h3><h3>Answer:</h3>

The answer is

{6x}^{2}  + 36x + 54

<h3>Hope it helps.</h3>

Sorry for delay

3 0
3 years ago
HELP I NEED THIS DONE QUICKK CAN ANNYONE HELP???????????????????????????????????????????????????????????????????????????????????
natulia [17]
For the first question, it would be D: \frac{1}{3} ÷ 9. This is because to solve a division problem with fractions, you would need to multiply the first fraction by the reciprocal of the second fraction. For the second question, the answer would be D: 32. This can be solved by dividing 8 by \frac{1}{4} or 0.25. For the third question, it would be D. \frac{1}{12}. This can be solved by dividing \frac{1}{4} by 3. For the fourth question, the answer would be \frac{1}{12}. This can be found by flipping the 4, which would make it look like \frac{1}{4}, and multiplying it by \frac{1}{3}. For the last question, 1 would be B, 2 would be C, 3 would be C, and 4 would be A.

Hope this helps ^-^
6 0
3 years ago
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