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olganol [36]
3 years ago
15

In a couple of sentences and in your own words describe in what ways horizontal, vertical, and oblique asymptotes can be identif

ied.
Mathematics
1 answer:
drek231 [11]3 years ago
5 0
A horizontal asymptote is one in which y has a limit as x approaches positive or negative infinite. It is usually due to both the denominator and the numerator having the same highest degree term, and the coefficient created by their proportion serves as the asymptote. For example, (2x^2 + 1) / (3x^2) would have a horizontal asymptote of 2/3

A vertical asymptote is an x value at which y approaches infinite. One example includes when the denominator of the function approaches zero at a certain point. For example, (x^2 + 3) / (x + 1) has a vertical asymptote at x=-1, since the denominator approaches zero as x approaches this point. 

For an oblique asymptote, y generally takes the form of a linear function as x approaches infinite. This is the case when the highest term in numerator is one degree higher than the highest degree term in the denominator. 

Examples include (5x^2 + 2) over 2x, where the oblique asymptote is (5/2)x, and even the linear function 2x+3 has an oblique asymptote of 2x
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Whst is 15 divided by 6 2/3 equals
PolarNik [594]
First you make 15 a fraction by putting it over 1.
Then you make 6 2/3 a mixed fraction.
To do this, you multiply 6 with 3 and add 2 to it. Then you put the number over 3.
We get
6 X 3 = 18
18 +2 = 20
20/3

Now, we divide 15/1 with 20/3.
When we divide it, we actually cross multiply it. Basically, we flip the fraction and multiply it.

So we get 15/1 X 3/20 = \frac{15 X 3}{1 X 20}.

We get 45/20 which can be simplified to 9/5 which can be simplified to 2  1/4.

So the answer is 9/4 or 2  1/4.
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2 years ago
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Solve the equation for principal values of x. Express solutions in degrees.
Hitman42 [59]

Option C:

x = 90°

Solution:

Given equation:

\sin x=1+\cos ^{2} x

<u>To find the degree:</u>

\sin x=1+\cos ^{2} x

Subtract 1 + cos²x from both sides.

\sin x-1-\cos ^{2} x=0

Using the trigonometric identity:\cos ^{2}(x)=1-\sin ^{2}(x)

\sin x-1-\left(1-\sin ^{2}x\right)=0

\sin x-1-1+\sin ^{2}x=0

\sin x-2+\sin ^{2}x=0

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Let sin x = u

u^2+u-2=0

Factor the quadratic equation.

(u+2)(u-1)=0

u + 2 = 0,  u – 1 = 0

u = –2, u = 1

That is sin x = –2, sin x = 1

sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.

sin x = 1

The value of sin is 1 for 90°.

x = 90°.

Option C is the correct answer.

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2 years ago
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Answer:

3x + 14 items

Step-by-step explanation:

First plant produces 5x + 11 items

Second plant produces 2x - 3 items

First plant production - second plant production = 5x + 11 - (2x - 3)

5x + 11 - 2x + 3 = 3x + 14 items

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