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Shkiper50 [21]
3 years ago
7

An airplane travels 720 in 3 hours with the wind. The return trip against the wind takes 4 hours. What is the wind speed and the

speed of the airplane in still air?
Mathematics
1 answer:
anyanavicka [17]3 years ago
4 0

Answer:

Wind speed = 30 per hour, Airplane speed = 210 per hour.

Step-by-step explanation:

Given:

An airplane travels 720 in 3 hours with the wind.

The return trip against the wind takes 4 hours.

Question asked:

What is the wind speed and the speed of the airplane in still air ?

Solution:

First of all we will find speed of airplane with the wind:-

Speed=\frac{Distance}{Time}

         =\frac{720}{3} \\ \\ =240

Now, let speed of plane = p

And let speed of wind = w

Speed of of airplane with the wind will be:-

p+w=240\ (equation\ 1)

Similarly, we will find speed of airplane against the wind:-

Speed=\frac{Distance}{Time}

         =\frac{720}{4} \\ \\ =180

Speed of airplane against the wind will be:-

p-w=180\ (equation\ 2)

Adding equation 1 and 2:-

p+w+p-w=240+180\\ \\ 2p=420\\ \\ Dividing\ both\ sides \ by \ 2\\ \\ \frac{2p}{2} =\frac{420}{2} \\ \\ p=210

Speed of plane = p = 210 per hour.

Speed of wind = w = ?

<u>Taking from equation 1:-</u>

p+w=240\\ \\ 210+w=240\\ \\ w=240-210\\ \\ w=30\ per \ hour

Speed of wind = 30 per hour.

Therefore, the wind speed is 30 per hour and speed of the airplane in still air is 210 per hour.

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Answer:

The answer is x = 5.

Step-by-step explanation:

Given:

Δ ABC is an Isosceles triangle with AB = CA

   m∠ ABC = ( 6x + 4 )°

   m∠ BAC = 73°

   m∠ BCA = ( 8y - 7 )°

To Find:

x = ?

Solution:

Properties of an Isosceles Triangle.

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  2. Any two sides are equal.

Here , Δ ABC is an Isosceles triangle with AB = CA

∴  m∠ BAC = m∠ BCA

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Property of a Triangle is Sum of the measures of the angle of a triangle is 180°.

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Substituting the values we get,

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