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3 years ago

What type of resource is corn?

Physics

1 answer:

muminat3 years ago

7 0

I believe Corn is a natural resource. It is a type of cereal plant grains, grown on Farms.

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How is your sense of well-being related to your ability to persevere through a challenge?

eduard

Your sense of well being related to your ability to persevere through a challenge because you being fit gives you boost of you being able to things than if your not really in shape so you being in shape help you get through challenges and your stamina is more stable

6 0

3 years ago

A capacitor in an LC oscillator experiences a maximum potential difference of 88V and a maximum energy of 2002 uJ. At a certain

VLD [36.1K]

Answer:

Explanation:

maximum energy of capacitor

E = 1/2 C V ²

C is capacitance of capacitor and V is potential difference

given V = 88 V

E = 2002 x 10⁻⁶ J

Putting the values

2002 x 10⁻⁶ = 1/2 x C x 88²

C = .517 x 10⁻⁶ F .

In the second case

Energy E = 125 x 10⁻⁶ J .

C = .517 x 10⁻⁶

V = ?

E = 1/2 C V ²

125 x 10⁻⁶ = 1/2 x .517 x 10⁻⁶ x V²

V² = 483.55

V = 21.98 V .

6 0

4 years ago

A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, wha

anygoal [31]

<span>F = m*a = 7000kg * 9.8N/kg = 68,600 N.

68,600 N is your answer
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3 0

3 years ago

The drawing shows a tire of radius R on a moving car

masha68 [24]

Answer:

H / R = 2/3

Explanation:

Let's work this problem with the concepts of energy conservation. Let's start with point P, which we work as a particle.

Initial. Lowest point

Em₀ = K = 1/2 m v²

Final. In the sought height

$Em_{f}$ = U = mg h

Energy is conserved

Em₀ = $Em_{f}$

½ m v² = m g h

v² = 2 gh

Now let's work with the tire that is a cylinder with the axis of rotation in its center of mass

Initial. Lower

Em₀ = K = ½ I w²

Final. Heights sought

Emf = U = m g R

Em₀ = $Em_{f}$

½ I w² = m g R

The moment of inertial of a cylinder is

I = $I_{cm}$ + ½ m R²

I= ½ $I_{cm}$ + ½ m R²

Linear and rotational speed are related

v = w / R

w = v / R

We replace

½ $I_{cm}$ w² + ½ m R² w² = m g R

moment of inertia of the center of mass

$I_{cm}$ = ½ m R²

½ ½ m R² (v²/R²) + ½ m v² = m gR

m v² ( ¼ + ½ ) = m g R

v² = 4/3 g R

As they indicate that the linear velocity of the two points is equal, we equate the two equations

2 g H = 4/3 g R

H / R = 2/3

7 0

3 years ago

¿Por qué crees que se debe estudiar la física?

Akimi4 [234]

No se porque?

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6 0

3 years ago

Read 2 more answers