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gtnhenbr [62]
3 years ago
9

If the horse lifts a 50 kilogram mass a vertical distance of 3 meters in 2 seconds, what is the horse’s minimum power output?

Physics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

735watts

Explanation:

Power = Force*distance/time

Given

Force = mg = 50 * 9.8'

Force = 490N

distance = 3m

time = 2s

Substitute

Power = 490*3/2

Power = 1470/2

Power = 735Watts

Hence the minimum power output is 735watts

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A block of 1 kg with a speed 1 m/s hits a spring placed horizontally as shown in the figure. If spring constant is 1000 N/m, fin
Evgen [1.6K]

Answer:

0.0316 m

Explanation:

Wok done = Energy change

Work done on the spring = Energy change of the block

  Elastic Potential stored = Kinetic energy of the block

\frac{1}{2} kx^{2} = \frac{1}{2} mv^{2}

                              x = \sqrt{v^{2}\frac{m}{k}  }

                              x = \sqrt{1^{2}\frac{1}{1000}  }

                              x = 0.0316 m

k = spring constant

m = mass of block

v = velocity of the block

x = compression of spring

8 0
3 years ago
An airplane travels directly from Washington, D.C., to Atlanta, Georgia, a distance of 850 km at a velocity of 425 km/h southwes
Sloan [31]

Answer:

obviously 2 hours cuz 850/425

Explanation:

4 0
3 years ago
Suppose you want to design an air bag system that can protect the driver at a speed 100 km/h (60 mph) if the car hits a brick wa
34kurt

When solving question that contains equations and the use mathematical computations, It is always ideal to list the parameters given.

Now, given that:

  • the speed of the car which is the initial velocity (u) = 100 km/h before it hits the wall.
  • after hitting the wall, the final velocity will be (v) = 0 km/h

Assumptions:

  • Suppose we make an assumption that the distance travelled during the collision of the car with the brick wall (S) = 1 m
  • That the car's acceleration is also constant.

∴

For a motion under constant acceleration, we can apply the kinematic equation:

\mathsf{v^2 = u^2 + 2as}

where;

v = final velocity

u = initial velocity

a = acceleration

s = distance

From the above equation, making acceleration (a) the subject of the formula:

\mathsf{v^2 - u^2 =2as }

\mathsf{a = \dfrac{v^2 - u^2 }{2s}}

The initial velocity (u) is given in km/h, and we need to convert it to m/s as it has an effect on the unit of the acceleration.

since 1 km/h = 0.2778 m/s

100 km/h = 27.78 m/s

\mathsf{a = \dfrac{(0)^2 - (27.78)^2 }{2(1)}}

\mathsf{a = \dfrac{- 771.7284 }{2}}

a = - 385.86 m/s²

Similarly, from the kinematic equation of motion, the formula showing the relation between time, acceleration and velocity is;

v = u + at

where;

v = 0

-u = at

\mathsf{t = \dfrac{-u}{a}}

\mathsf{t = \dfrac{-27.78}{-385.86}}

t = 0.07 seconds

An airbag is designed in such a way as to prevent the driver from hitting on the steering wheel or other hard substance that could damage the part of the body. The use of the seat belt is to keep the driver in shape and in a balanced position against the expansion that occurred by the airbag during the collision on the brick wall.

Thus, we can conclude that the airbag must be inflated at 0.07 seconds faster before the collision to effectively protect the driver.

Learn more about the kinematic equation here:

brainly.com/question/11298125?referrer=searchResults

3 0
3 years ago
An electron initially has a speed 16 km/s along the x-direction and enters an electric field of strength 27 mV/m that points in
weqwewe [10]

Answer:

a)t=1.4\times 10^{-5}\ s

b)S= 46.4 cm

Explanation:

Given that

Velocity = 16 Km/s

V= 16,000 m/s

E= 27 mV/m

E=0.027 V/m

d= 22.5 cm

d= 0.225 m

a)

lets time taken by electron is t

d = V x t

0.225 = 16,000 t

t=1.4\times 10^{-5}\ s

b)

We know that

F = m a = E q                    ------------1

Mass of electron ,m

m=9.1\times 10^{-31}\ kg

Charge on electron

q=1.6\times 10^{-19}\ C

So now by putting the values in equation 1

a=\dfrac{E q}{m}

a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2

a=4.74\times 10^{9}\ m/s^2

S= ut+\dfrac{1}{2}at^2

Here initial velocity u= 0 m/s

S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m

S=0.464 m

S= 46.4 cm

S is the deflection of electron.

4 0
3 years ago
Read 2 more answers
As a prank, your friends have kidnapped you in your sleep, and transported you out onto the ice covering a local pond. When you
Ilia_Sergeevich [38]

Answer:

Explained

Explanation:

You should throw your boot in the direction away from the closest shore so that the reaction force is towards the closest shore.

8 0
3 years ago
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