Answer:
<em>The cliff is 5916.75 m far</em>
Explanation:
Echo: This is a sound heard after the reflection of sound wave from a plane surface.
v = 2x/t........................... Equation 1
making x the subject of the equation above,
x = vt/2........................... Equation 2
Where v = speed of sound in air, x = distance of the cliff, t = time to produce an echo
<em>Given: t = 34.50 s,</em>
<em>Constant: v = 343 m/s</em>
<em>Substituting these values into equation 2,</em>
<em>x = 343×34.5/2</em>
<em>x = 5916.75 m.</em>
<em>Thus the cliff is 5916.75 m far</em>
Answer:
0.65 A.
Explanation:
Given:
Pmax = 10 W
R = 23.9 Ω
Formula for calculating power,
P = I × V
= I^2 × R
I^2 = 10/23.9
I = 0.65 A.
Answer:
The magnitude of the magnetic force exerted on the moving charge by the current in the wire is 2.18 x N
The direction of the magnetic force exerted on the moving charge by the current in the wire is radially inward
Explanation:
given information:
current, I = 3 A
= +6.5 x C
r = 0.05 m
v = 280 m/s
and direction of the magnetic force exerted on the moving charge by the current in the wire, we can use the following formula:
F = qvB sin θ
where
F = magnetic force (N)
q = electric charge (C)
v = velocity (m/s)
θ = the angle between the velocity and magnetic field
to find B we use
B = μI/2πr
μ = 4π x or 1.26 x N/ , thus
B = 4π x x 3 / 2π(0.05)
= 1.2 x T
Now, we can calculate the magnitude force
F = qvB sin θ
θ = 90°, because the speed and magnetic are perpendicular
F = 6.5 x x 280 x 1.2 x sin 90°
= 2.18 x N
Using the hand law, the magnetic direction is radially inward
Answer:
3.125J
Explanation:
K.E.= 1/2(mass)(velocity)^2
K.E.=1/2(0.25)(5)^2=3.125