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2 years ago

1. What will happen to the brightness of the light bulb if the switch in this circuit is suddenly closed?

Physics

1 answer:

bazaltina [42]2 years ago

6 0

Answer:

There is no closed-loop path for the current to flow through the circuit.When the switch is closed,the light bulb operates since the current flows through the circuit.The bulb glows at its full brightness since its receives its full 120 volts and has the design current flow.

Explanation:

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Which of the following graphs best represents the relationship between the gravitational potential energy of a freely falling ob

VLD [36.1K]

Answer:

The last graph.

Explanation:

Gravitational potential energy is the energy possessed by a body at a given height from the Earth's surface.

The formula to find the gravitational potential energy is given as:

$U=mgh$

Where, 'U' is the gravitational potential energy.

'm' is the mass of the body.

'g' is the acceleration of the body due to gravity.

'h' is the height of the body above the Earth's surface.

So, from the above equation, it is clear that, gravitational potential energy is directly proportional to the height. So, as height increases, the gravitational potential energy increases. At the surface of Earth, where, height is 0, the gravitational potential energy is also zero.

Therefore, the correct graph is a straight line with positive slope and passing through the origin. So, the last option is the correct one.

3 0

2 years ago

Ch 27 HW Exercise 27.12 10 of 20 Constants A horizontal rectangular surface has dimensions 2.80 cm by 3.15 cm and is in a unifor

deff fn [24]

Answer:

Magnetic field, B = 0.88 T

Explanation:

It is given that,

The dimension of rectangular surface is 2.80 cm by 3.15 cm. The area of rectangular surface is, $A=8.82\ cm^2=0.000882\ m^2$

Angle between the uniform magnetic field and the horizontal, $\theta=31$

Magnetic flux, $\phi=4\times 10^{-4}\ Wb$

Let B is the magnitude of magnetic field in which the rectangular surface is placed. It is given by :

$\phi=BA\ cos\theta$

$\theta$ is the angle between magnetic field and the area

Here, $\theta=90-31=59^{\circ}$

$B=\dfrac{\phi}{A\ cos\theta}$

$B=\dfrac{4\times 10^{-4}}{0.000882\times cos(59)}$

B = 0.88 T

So, the magnitude of magnetic field is 0.88 T. Hence, this is the required solution.

7 0

2 years ago

What is a gravitational field and how its strength be measured

Yakvenalex [24]

A gravitational field is the field generated by a massive body, that extends into the entire space. Every object with mass m experiences a force F when immersed in a gravitational field. The intensity of the force is equal to
$F= \frac{GM}{r^2} m$
where $G=6.67 \cdot 10^{-11} m^3 Kg^{-1} s^{-2}$ is the gravitational constant, M is the mass of the source of the field (e.g. the mass of a planet), and r is the distance between the object and the source of the field. The force is always attractive.

A possible way to measure the intensity of a gravitational field is by measuring the acceleration a of the object immersed in this field. In fact, for Newton's second law we have:
$F=ma$
but since
$F= \frac{GM}{r^2} m$
we can write
$a = \frac{GM}{r^2}$
Therefore, by measuring the acceleration of the object, we also measure the intensity of the field.

5 0

2 years ago

What are the coefficients in this expression?

skad [1K]

6 and $\frac{1}{3}$