Answer:
0° C
Explanation:
Given that
Mass of ice, m = 50g
Mass of water, m(w) = 50g
Temperature of ice, T(i) = 0° C
Temperature of water, T(w) = 80° C
Also, it is known that
Specific heat of water, c = 1 cal/g/°C
Latent heat of ice, L(w) = 89 cal/g
Let us assume T to be the final temperature of mixture.
This makes the energy balance equation:
Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C
m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have
50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)
4000 + 50T = 4000 - 50T
0 = 100 T
T = 0° C
Thus, the final temperature is 0° C
The higher you go the more potential energy there is, and the lower it is the more kinetic energy there is, so the more kinetic energy there is the higher the ball will bounce.
Answer:
The maximum change in flux is 
The average induced emf 
Explanation:
From the question we are told that
The speed of the technician is 
The distance from the scanner is 
The initial magnetic field is 
The final magnetic field is 
The diameter of the loop is 
The area of the loop is mathematically represented as
![A = \pi [\frac{D}{2} ]^2](https://tex.z-dn.net/?f=A%20%20%3D%20%20%5Cpi%20%5B%5Cfrac%7BD%7D%7B2%7D%20%5D%5E2)


At maximum the change in magnetic field is mathematically represented as

=> 

The average induced emf is mathematically represented as


