Answer:
W = 529.2 N
Explanation:
We can solve this problem using the translational equilibrium equation, where the forces are the weight of the sergeant and the thrust of the water given by Archimedes' principle
B - W = 0
where the thrust is
B = ρ g V_liquid
The volume of the displaced liquid is
V = A h
we substitute
ρ g A h = W
We reduce the magnitudes to the SI system
h = 2.7 cm = 0.027 m
ρ = 1 g / cm3 = 1000 kg / m³
let's calculate
W = 1000 9.8 2 0.027
W = 529.2 N
Answer:
1) The car is slowing down
2) A = 40N forward & B = 25N up
Explanation:
Whenever you're dealing with forces on moving objects, it is important to look at each of the numbers and the directions they're going in.
With the racecar, we see it has four forces on it, 2,000 N up and down, 8,000 back, and 6,000 N forward. Now, each of these forces are going in their respective directions, but they are most in comparison with the force going in the opposite direction (vertical axis, horizontal axis). The two 2,000 N forces will cancel each other out since there is an equal force in both directions, causing a net force of <u>0 N on the vertical axis</u>. This is because the car is most likely moving on a flat surface. As for the horizontal axis, we simply subtract 6,000 & 8,000 to get a net force of <u>-2,000 N in the backwards direction</u>, telling us that the car is slowing down.
As for the boxes, we see the same vertical and horizontal axes, but separated to each box. Box A has a net force of <u>40 N in the forward direction</u> and Box B has a net force of <u>25 N in the upward direction</u>.
Its D because of the emission spectra
Work done (J) = Force (N) x Distance (m)
Answer:
d = 8.4 cm
Explanation:
In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:
(1)
A: amplitude of the oscillation
w: angular speed of the oscillation = 2
f
f: frequency = 0.17Hz
The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:

Then, you solve for A in the equation (1) and replace the values of the parameters:

The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:
d = 2A = 2(4.2cm) = 8.4cm