Ask question

Ask question

All categories

3 years ago

9

Sonar signals and infrared light are are used to send messages to submarines deep under water. If we compare the two signals, wh

ich statement describes a difference between the two?

1 answer:

WARRIOR [948]3 years ago

6 0

What are the statement choices?

You might be interested in

1. A baseball is thrown horizontally at 45 m/s. The ball slows down at a rate of 5 m/s?

meriva

Answer:

Explanation:

a )

initial velocity u = 45 m/s

acceleration a = - 5 m/s²

final velocity v = 0

v = u - at

0 = 45 - 5 t

t = 9 s

b )

s = ut - 1/2 at²

= 45 x 9 - .5 x5x 9²

405 - 202.5

202.5 m

2 )

a )

s = ut + 1/2 a t²

u = 0

s = 1/2 at²

= .5 x 9.54 x 6.5²

= 201.5 m

b )

v = u + at

= 0 + 9.54 x 6.5

= 62.01 m / s

3

a )

acceleration = (v - u) / t

= (34 - 42) / 2.4

= - 3.33 m /s²

b )

v² = u² - 2 a s

34² = 42² - 2 x 3.33² s

s = 27.41 m

c )

Average velocity

Total displacement / time

= 27.41 / 2.4

= 11.42 m /s

4 )

a )

v = u + at

v = 0 + 3 x 4

= 12 m /s

b )

s = ut + 1/2 a t²

= o + .5 x 3 x 4²

= 24 m

8 0

3 years ago

At each of the designated points, rotate the given vector to indicate the direction of the force exerted by the water on either

GrogVix [38]

Answer:

The direction of the force at A and B is perpendicular to the walls of the container.

The direction of the force at C is down.

The direction of the force in D is up

The direction of the force at E is to the left.

The attached figure shows the forces exerted by the water at points A, B, C, D and E.

Explanation:

The water is in contact with the bowl and with the fish. It exercises at points A, B, C, D and E, but the direction is different from the force.

The fish has a buoyant force on the water and that direction is up. The direction of at point D is up.

The column of water on the fish has a downward force, therefore the direction of the force at point C is down. The water column to the right of the fish has a force to the left, and the direction at point E is to the left.

The water will exert a force on the walls of the container and this force at points A and B is a on the walls of the container.

4 0

4 years ago

I NEED HELP PLEASE, THANKS! :)

Zina [86]

Answer:

charge C = greatest net force

charge B = the smallest net force

ratio = 9 : 1

Explanation:

we know that in Electrostatic Forces, when 2 charges are at same sign then they repel each other and if they are different signed charges then they attract each other

so as per Coulomb's formula of Electrostatic Forces

F = $\frac{k\ q_1\ q_2}{r^2}$ .....................1

and here k is 9 × $10^9$ N.m²/c² and we consider each charge at distance d

so two charge force at A to B is

F1 = $\frac{k\ q^2}{d^2}$

and force between charges at A to C, at 2d distance

F1 = $\frac{k\ q^2}{(2d)^2}$ = $\frac{k\ q^2}{4d^2}$

force between charges at A to D, 3d distance

F1 = $\frac{k\ q^2}{(3d)^2}$ = $\frac{k\ q^2}{9d^2}$

so

Charge a It receives force to the left from b and c and to the right from d

so at a will be

F(a) = -F1 - F2 + F3 ....................2

put here value

F(a) = $-\frac{k\ Q^2}{d^2}-\frac{k\ Q^2}{4d^2}+\frac{k\ Q^2}{9d^2}$

solve it

F(a) = $\frac{k\ q^2}{d^2}(-1-\frac{1}{4}+\frac{1}{9})$

F(a) = $-\frac{41}{36}\ F1$ = 1.13 F1

and

Charge b It receives force to the right from a and d and to the left from c

F(b) = F1 - F1 + F2 ....................3

F(b) = $\frac{k\ q^2}{d^2}-\frac{k\ q^2}{d^2}+\frac{k\ q^2}{4d^2}$

F(b) = $\frac{1}{4} \ F1$ = 0.25 F1

and

Charge c It receives forces to the right from all charges.

F(c) = F2 + F 1 + F 1 ....................4

F(c) = $\frac{k\ q^2}{4d^2}+\frac{k\ q^2}{d^2}+\frac{k\ q^2}{d^2}$

F(c) = $\frac{9}{4} \ F1$ = 2.25 F1

and

Charge d It receives forces to the left from all charges

F(d) = - F3 - F2 -F 1 ....................5

F(d) = $-\frac{k\ q^2}{9d^2}-\frac{k\ q^2}{4d^2}-\frac{k\ q^2}{d^2}$

so

F(d) = $-\frac{49}{36} \ F1$ = 1.36 F1

and

now we get here ratio of the greatest to the smallest net force that is

ratio = $\frac{2.25}{0.25}$

ratio = 9 : 1

5 0

3 years ago

What is the kinetic energy of a 150 gram object moving at a velocity of 100 m/s?

Alex Ar [27]

Answer:

750 J

Explanation:

lets convert mass into kg first , 150 /1000 = 0.15 kg

kinetic energy = $\frac{mv^{2} }{2}$ = $\frac{0.15*100^{2} }{2} = 750 J$

3 0

3 years ago

What happened to the maximum height of consecutive swings

GarryVolchara [31]

Answer:

we need more info

Explanation:

3 0

3 years ago