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3 years ago

How do you find weight =mass×gravitational acceleration

2 answers:

7 0

That's a formula that shows the relationship between three quantities ...
weight, mass, and acceleration. If you know any two of them, then you
can use this formula to find the one you don't know.

Examples:

==> I have a rock with 2 kilograms of mass.
The gravitational acceleration on Earth is 9.8 m/s² .
How much does my rock weigh on Earth ?

   Weight = (mass) x (grav acceleration)
      = (2 kg) x (9.8 m/s²)
   = 19.6 newtons
      (about 4.41 pounds)

==> My brother weighs 770 newtons (about 173 pounds) on Earth.
   What is his mass ?

       Weight = (mass) x (grav acceleration)

   770 newtons = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s²:    770 newtons / 9.8 m/s² = mass

    78.57 kilograms = mass

==> When I went to the Moon, I took along my 2-kilogram rock.
   I weighed my rock on the Moon.
   It weighs 3.25 newtons (about 0.73 pound) there.
   What is the gravitational acceleration on the Moon ?

   Weight = (mass) x (grav acceleration)

   3.25 newtons = (2 kg) x (acceleration)

Divide each side
by 2 kilograms: (3.25 newtons)/(2 kg) = acceleration

    1.63 m/s² = grav acceleration on the Moon

lisov135 [29]3 years ago

6 0

By plugging in the variables duh. Hahhha so look at your problem and plug in the numbers to what they are.

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5 0

3 years ago

Read 2 more answers

A father racing his son has 1/3 the kinetic energy of the son, who has 1/4 the mass of the father. The father speeds up by 1.5 m

Feliz [49]

Explanation:

Let the speeds of father and son are $v_f\ and\ v_s$ . The kinetic energies of father and son are $K_f\ and\ K_s$ . The mass of father and son are $m_f\ and\ m_s$

(a) According to given conditions, $K_f=\dfrac{1}{3}K_s$

And $m_s=\dfrac{1}{4}m_f$

Kinetic energy of father is given by :

$K_f=\dfrac{1}{2}m_fv_f^2$ .............(1)

Kinetic energy of son is given by :

$K_s=\dfrac{1}{2}m_sv_s^2$ ...........(2)

From equation (1), (2) we get :

$\dfrac{v_f^2}{v_s^2}=\dfrac{1}{12}$ ..............(3)

If the speed of father is speed up by 1.5 m/s, so the ratio of kinetic energies is given by :

$\dfrac{K_f}{K_s}=\dfrac{1/2m_f(v_f+1.5)^2}{1/2m_sv_s^2}$

$v_s^2=4(v_f+1.5)^2$

Using equation (3) in above equation, we get :

$v_f=\dfrac{1.5}{\sqrt3-1}=2.04\ m/s$

(b) Put the value of $v_f$ in equation (3) as :

$v_s=7.09\ m/s$

Hence, this is the required solution.

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3 years ago

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Answer:

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Answer:

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Answer:

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Explanation:

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3 years ago