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viva [34]
3 years ago
5

How do you find weight =mass×gravitational acceleration

Physics
2 answers:
Artist 52 [7]3 years ago
7 0
That's a formula that shows the relationship between three quantities ...
weight, mass, and acceleration.  If you know any two of them, then you
can use this formula to find the one you don't know.

Examples:

==>  I have a rock with 2 kilograms of mass.
        The gravitational acceleration on Earth is 9.8 m/s² .
        How much does my rock weigh on Earth ?

         Weight = (mass) x (grav acceleration)
                      = (2 kg) x (9.8 m/s²)
                                                       =  19.6 newtons
                                                  (about 4.41 pounds)

==>  My brother weighs 770 newtons (about 173 pounds) on Earth.
         What is his mass ?

                               Weight = (mass) x (grav acceleration)

                               770 newtons = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s²:           770 newtons / 9.8 m/s² = mass

                                        78.57 kilograms = mass

==> When I went to the Moon, I took along my 2-kilogram rock.
         I weighed my rock on the Moon. 
         It weighs 3.25 newtons  (about 0.73 pound) there.
         What is the gravitational acceleration on the Moon ?

                                   Weight = (mass) x (grav acceleration)

                                   3.25 newtons = (2 kg) x (acceleration)

Divide each side
by  2 kilograms:        (3.25 newtons)/(2 kg)  =  acceleration

                                    1.63 m/s² = grav acceleration on the Moon 

          


lisov135 [29]3 years ago
6 0
By plugging in the variables duh. Hahhha so look at your problem and plug in the numbers to what they are.

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The resistance of a wire depends upon the material's resistivity and the length and cross‑sectional area of the wire. What will
andriy [413]

Answer:

R' = 4R

The resistance will become 4 times the initial value.

Explanation:

The resistance of a wire at room temperature, is given by the following formula:

R = ρL/A   ----------- equation 1

where,

R = Resistance of wire

ρ = resistivity of the material

L = Length of wire

A = Cross-sectional area of wire

Now, if the length (L) is multiplied by 4, then resistance will become:

R' = ρ(4L)/A

R' = 4 (ρL/A)

using equation 1:

<u>R' = 4R</u>

<u>The resistance will become 4 times the initial value.</u>

6 0
3 years ago
When two resistors are wired in series with a 12 V battery, the current through the battery is 0.33 A. When they are wired in pa
MA_775_DIABLO [31]

Answer:

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2

In parallel

\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}

\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0

Solving the above quadratic equation

\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}

\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

6 0
3 years ago
1. If I travel 50 miles in 5minutes, how fast am I going?
Anarel [89]

Answer:

10 miles a min

Explanation:

math

3 0
3 years ago
What is the wavelength of a radio photon from an "am" radio station that broadcasts at 1160 kilohertz?what is its energy?
netineya [11]
Given:
f = 1160 kHz = 1160 x 10³ Hz
The velocity is c = 3 x 10⁸ m/s, the velocity of light (approximmately).

Calculate the wavelength, λ.
c = fλ
λ = c/f = (3 x 10⁸ m/s)/(1160 x 10³ 1/s) = 258.62 m

Answer: 258.6 m
7 0
3 years ago
A thin rod of length L and total charge Q has the nonuniform linear charge distribution λ(x)=λ0x/L, where x is measured from the
marissa [1.9K]

Answer:

Explanation:

λ(x) = λo x/ L

(a) The total charge is Q.

Q=\int_{0}^{L}dq

Q=\int_{0}^{L}\frac{\lambda _{0}x}{L}dx

Q=\frac{\lambda _{0}}{2L}\left ( x^{2} \right )_{0}^{L}

Q=\frac{\lambda _{0}}{2L}

λo = 2Q/L

(b)

Let at a distance x from the origin the charge is dq.

so, dq = (2Q/L) x/ L dx

dq=\frac{2Qx}{L^{2}}dx

The potential due to this small charge at a distance d to the left of origin

dV = \frac{KdQ}{d+x}

\int_{0}^{V}dV = \frac{2KQ}{L^{2}}\int_{0}^{L}\frac{xdx}{d+x}

V = \frac{2KQ}{L^{2}}\int_{0}^{L}\left ( 1- \frac{d}{d+x}\right )dx

V = \frac{2KQ}{L^{2}}\times \left ( x-dln(d+x) \right )\int_{0}^{L}

V = \frac{2KQ}{L^{2}}\times \left ( L-dln(d+L)-0+dlnd \right )

V = \frac{Q}{4\pi \epsilon _{0}L^{2}}\times \left ( L+d\times ln\left (\frac{d}{d+L}  \right )\right )

4 0
3 years ago
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