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2 years ago

How do you find weight =mass×gravitational acceleration

2 answers:

7 0

That's a formula that shows the relationship between three quantities ...
weight, mass, and acceleration. If you know any two of them, then you
can use this formula to find the one you don't know.

Examples:

==> I have a rock with 2 kilograms of mass.
The gravitational acceleration on Earth is 9.8 m/s² .
How much does my rock weigh on Earth ?

   Weight = (mass) x (grav acceleration)
      = (2 kg) x (9.8 m/s²)
   = 19.6 newtons
      (about 4.41 pounds)

==> My brother weighs 770 newtons (about 173 pounds) on Earth.
   What is his mass ?

       Weight = (mass) x (grav acceleration)

   770 newtons = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s²:    770 newtons / 9.8 m/s² = mass

    78.57 kilograms = mass

==> When I went to the Moon, I took along my 2-kilogram rock.
   I weighed my rock on the Moon.
   It weighs 3.25 newtons (about 0.73 pound) there.
   What is the gravitational acceleration on the Moon ?

   Weight = (mass) x (grav acceleration)

   3.25 newtons = (2 kg) x (acceleration)

Divide each side
by 2 kilograms: (3.25 newtons)/(2 kg) = acceleration

    1.63 m/s² = grav acceleration on the Moon

lisov135 [29]2 years ago

6 0

By plugging in the variables duh. Hahhha so look at your problem and plug in the numbers to what they are.

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A particle moves along the x axis from the origin. The magnitude of the position vector at time t is

Maurinko [17]

1) The average velocity is $-2.1\cdot 10^5 m/s$

2) The instantaneous velocity is $64t-260t^3$

Explanation:

The average velocity of an object is given by

$v=\frac{d}{t}$

where

d is the displacement

t is the time elapsed

In this problem, the position of the particle is given by the function

$x(t) = 32t^2 - 65t^4$

where t is the time.

The position of the particle at time t = 6 sec is

$x(6) = 32(6)^2 - 65(6)^4=-83,088 m$

While the position at time t = 12 sec is

$x(12)=32(12)^2-65(12)^4=-1,343,232 m$

So, the displacement is

$d=x(12)-x(6)=-1,343,232-(-83,088)=-1,260,144 m$

And therefore the average velocity is

$v=\frac{-1,260,144 m}{12 s- 6 s}=-2.1\cdot 10^5 m/s$

The instantaneous velocity of a particle is given by the derivative of the position vector.

The position vector is

$x(t) = 32t^2 - 65t^4$

By differentiating with respect to t, we find the velocity vector:

$v(t) = x'(t) = 2\cdot 32 t - 4\cdot 65 t^3 = 64t - 260 t^3$

Therefore, the instantaaneous velocity at any time t can be found by substituting the value of t in this expression.

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6 0

3 years ago

Sound waves produced by a source pass a point five times every second. Which of the following choices correctly describes the pe

Ugo [173]

The period is 1/5 second, and the frequency is 5 Hz.

Explanation:

Let's start by reviewing some definitions about waves:

- The period of a wave is the time taken for the wave to make one complete cycle. It is indicated with T and it is measured in seconds (s)

- The frequency of a wave is the number of complete cycles made by the wave in one second. It is indicated with f and it is measured in Hertz (Hz). It is equal to the reciprocal of the period:

$f=\frac{1}{T}$

where f is the frequency and T is the period.

In this problem, we have a wave that passes a given point five time per second. This means that the number of oscillations per second is five, and so its frequency is:

$f=\frac{5 cycles}{1 sec}=5 Hz$

It follows than the period of the wave is:

$T=\frac{1}{f}=\frac{1}{5}s$

Therefore, the correct statement is

The period is 1/5 second, and the frequency is 5 Hz.

Learn more about waves, frequency and period:

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3 0

3 years ago

A 1.2 KG rubber ball is being thrown in the air if the ball is traveling at 2.0 M/S when it is 3.0 M off the ground what is the

Vitek1552 [10]

Answer:

37.7 J

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6 0

2 years ago

The action force is the balloon pushing the air out. What is the magnitude of the reaction force of the air pushing on the ballo

aleksley [76]

Understanding Newtons second law that everything has an equal and opposite reaction. The reaction force from a balloons air being pushed out is the preasurized air it had to push out into the open air.

7 0

3 years ago

Read 2 more answers

A force of 200N due South and another force of 300N due East each act on an object simultaneously.

dangina [55]

Answer:

a) 500

b)-500, north west

Explanation:

a) sum of F= F1+F2= 200+300= 500

b) sum of forces=0

so 200+300-500+0

4 0

1 year ago