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3 years ago

How do you find weight =mass×gravitational acceleration

2 answers:

7 0

That's a formula that shows the relationship between three quantities ...
weight, mass, and acceleration. If you know any two of them, then you
can use this formula to find the one you don't know.

Examples:

==> I have a rock with 2 kilograms of mass.
The gravitational acceleration on Earth is 9.8 m/s² .
How much does my rock weigh on Earth ?

   Weight = (mass) x (grav acceleration)
      = (2 kg) x (9.8 m/s²)
   = 19.6 newtons
      (about 4.41 pounds)

==> My brother weighs 770 newtons (about 173 pounds) on Earth.
   What is his mass ?

       Weight = (mass) x (grav acceleration)

   770 newtons = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s²:    770 newtons / 9.8 m/s² = mass

    78.57 kilograms = mass

==> When I went to the Moon, I took along my 2-kilogram rock.
   I weighed my rock on the Moon.
   It weighs 3.25 newtons (about 0.73 pound) there.
   What is the gravitational acceleration on the Moon ?

   Weight = (mass) x (grav acceleration)

   3.25 newtons = (2 kg) x (acceleration)

Divide each side
by 2 kilograms: (3.25 newtons)/(2 kg) = acceleration

    1.63 m/s² = grav acceleration on the Moon

lisov135 [29]3 years ago

6 0

By plugging in the variables duh. Hahhha so look at your problem and plug in the numbers to what they are.

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Please help i'm going to throw up from stress

Eddi Din [679]

Answer:

Explanation:

First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.

120.g = .1200 kg of ethyl alcohol. Now for the formula:

$t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})}$ where spheat is specific heat.

Filling that horrifying-looking formula in with some values:

$16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)}$ and

$16.0=\frac{83640x+2928}{4182x+292.8}$ and

16(4182x + 292.8) = 83640x + 2928 and

66912x + 4684.8 = 83640x + 2928 and

1756.8 = 16728x so

x = .105 kg and the amount of water added is 105 g

4 0

3 years ago

In science, a hypothesis must be true.

Anon25 [30]

I would believe that this is false.

6 0

4 years ago

A refrigerator removes 55.0 kcal of heat from the freezer and releases 73.5 kcal through the condenser on the back.How much work

sammy [17]

Here refrigerator removes 55 kcal heat from freezer

Refrigerator releases 73.5 kcal heat to surrounding

So here we can use energy conservation principle by II Law of thermodynamics

the law says that

$Q_1 = Q_2 + W$

here we know that

$Q_1$ = heat released to the surrounding

$Q_2$ = heat absorbed from freezer

W = work done by the compressor

now using above equation we can write

$73.5 = 55 + W$

$W = 73.5 - 55$

$W = 18.5 kcal$

So here compressor has to do 18.5 k cal work on it

5 0

3 years ago

A charge of q= +15 uC moves in a Northeast direction with a speed 5 m/s, 25 degrees East of a magnetic field, pointing North, wi

grin007 [14]

Explanation:

It is given that,

Magnitude of charge, $q=15\ \mu C=15\times 10^{-6}\ C$

It moves in northeast direction with a speed of 5 m/s, 25 degrees East of a magnetic field.

Magnetic field, $B=0.08\ j$

Velocity, $v=(5\ cos25)i+(5\ sin25)j$

$v=[(4.53)i+(2.11)j]\ m/s$

We need to find the magnitude of force on the charge. Magnetic force is given by :

$F=q(v\times B)$

$F=15\times 10^{-6}[(4.53i+2.11j)\times 0.08\ j]$

<em>Since</em>, $i\times j=k\ and\ j\times j=0$

$F=15\times 10^{-6}[(4.53i)\times (0.08)\ j]$

$F=0.00000543\ kN$

$F=5.43\times 10^{-6}\ kN$

So, the force acting on the charge is $5.43\times 10^{-6}\ kN$ and is moving in positive z axis. Hence, this is the required solution.

6 0

3 years ago

Read the following and identify the main parts of the experiment.

slava [35]

The independent variable refers to the type of socks (synthetic socks), the dependent variable is the number of blisters and the control is the two weeks that she switches back to the cotton socks.

<h3>What is the dependent variable?</h3>

In an experiment, the dependent variable is those being tested and changes according to the independent variable.

The control group is the set of experimental conditions that is used to compare a given outcome in an experiment.

In conclusion, The independent variable refers to the type of socks (synthetic socks), the dependent variable is the number of blisters and the control is the two weeks that she switches back to the cotton socks.

Learn more about the dependent variable here:

brainly.com/question/25223322

#SPJ1

4 0

2 years ago