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Mnenie [13.5K]
3 years ago
13

two forces P and Q pass through a point A which is 4 ft to the right of and 3 ft above a moment center O. force P is 200 lb dire

cted up to the right at 30degrees with the horizontal and force Q is 100 lb directed up to the left at 60degrees with the horizontal, determine the moment of the resultant of these two forces with respect to O.
Physics
1 answer:
valentinak56 [21]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

The moment of the resultant of these two forces with respect to O 376 lb-ft CCW which is <span>about moment center point O.</span>
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What are physical properties?
Blizzard [7]

I'm pretty sure that the answer is C

4 0
3 years ago
Earth moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is kilometers, and the
serious [3.7K]

Complete question is;

Earth moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is 149,598,000 kilometers, and the eccentricity is 0.0167. Find the minimum distance (perihelion) and the maximum distance (aphelion) of Earth from the sun

Answer:

Minimum distance = 147,099,713.4 km

Maximum distance = 152,096,286.6 km

Explanation:

The formula for the eccentricity of an ellipse is given by;

e = c/a

where;

c is distance from the center of the ellipse to the focus of the ellipse.

a is distance from the center of ellipse to a vertex.

From the question, we are given;

a = 149,598,000

e = 0.0167

Thus;

0.0167 = c/149,598,000

c = 0.0167 × 149,598,000

c = 2,498,286.6

Now, formula for the minimum distance (perihelion) is;

Minimum distance = a - c

Minimum distance = 149598000 - 2498286.6

Thus;

Minimum distance = 147,099,713.4 km

Similarly, formula for the maximum distance (aphelion) is;

Max distance = a + c

Max distance = 149598000 + 2498286.6

Maximum distance = 152,096,286.6 km

4 0
3 years ago
Suppose that 1000 pollen grains slam into the abdomen of a 5.0 g bee that is hovering just above the flower. the grain's mass is
BaLLatris [955]
<span>m1 = 5g = 0.005kg v1 = 0 m2 = 1.0 x 10^-7g = 1.0x10^-10kg v2 = 7.5 v3 = ? looks like you did the formula correctly m1v1 + m2v2 = (m1+m2)v3 0 + m2v2 = (m1+m2)v3 m2v2 / (m1+m2) = v3 (1.0x10^-10)(7.5) / (0.005 + 1.0x10^-10) = v3 1.5x10^-7 = v3 However, it said the bee gets hit by 1000 pollen grains, so I would guess you have to multiply 1.0 x 10^-10 by 1000 first, unless the total mass of the 1000 grains really is 1.0 x 10^-10.</span>
7 0
3 years ago
Read 2 more answers
edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
laila [671]

The displacement of Edward in the westerly direction is determined as 180.27 km.

<h3>Displacement of Edward</h3>

The displacement of Edward is calculated as follows;

R² = a² + b² - 2abcosθ

R² = 150² + 200² - 2(150 x 200) x cos60

R² = 32500

R = 180.27 km

Thus, the displacement of Edward in the westerly direction is determined as 180.27 km.

Learn more about displacement here: brainly.com/question/321442

#SPJ1

3 0
2 years ago
A 100-kg astronaut floating in space holds a 10-kg object. Then the object is tossed at 50 m/s. How fast does the astronaut go a
zlopas [31]

Answer:

velocity is 5 m/s

Explanation:

mass of astronaut (M)=100kg

mass of object (m)=10kg

Initially they are rest , so initial velocity (u)= 0 m/s

Final velocity of object ; v_1=10m/s

let final velocity of astronaut = v_2 (Unknown)

Now , By conservation of linear momentum

Initial momentum = Final momentum

(m + M)\times u = (m\times v_1) + (M\times v_2)

Now insert values

0 = (10 kg \times 50 m/s ) + (100 kg \: v_2)

Further simplifying

v_2=-\frac{500 kg-m/s}{100kg}

So,

v_2= -5\:m/s

So, velocity is 5 m/s (the negative sign is due to direction)

4 0
3 years ago
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