two forces P and Q pass through a point A which is 4 ft to the right of and 3 ft above a moment center O. force P is 200 lb dire
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Answer:
Explanation:
Consider two particles are initially at rest.
Therefore,
the kinetic energy of the particles is zero.
That initial K.E. = 0
The relative velocity with which both the particles are approaching each other is Δv and their reduced masses are
now, since both the masses have mass m
therefore,
= m/2
The final K.E. of the particles is
Distance between two particles is d and the gravitational potential energy between them is given by
By law of conservation of energy we have
Now plugging the values we get
This the required relation between G,m and d
We have here what is known as parallel combination of resistors.
Using the relation:
And then we can turn take the inverse to get the effective resistance.
Where r is the magnitude of the resistance offered by each resistor.
In this case we have,
(every term has an mho in the end)
To ger effective resistance take the inverse:
we get,
The potential difference is of 9V.
So the current flowing using ohm's law,
V = IR
will be, 0.0139 Amperes.
Using the relation:
And then we can turn take the inverse to get the effective resistance.
Where r is the magnitude of the resistance offered by each resistor.
In this case we have,
(every term has an mho in the end)
To ger effective resistance take the inverse:
we get,
The potential difference is of 9V.
So the current flowing using ohm's law,
V = IR
will be, 0.0139 Amperes.