I have the same question on a test I'm taking thanks
Answer:
<u>Pressure</u><u> </u><u>is</u><u> </u><u>8</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>pascals</u><u>.</u>
Step-by-step explanation:
Area:

Pressure:

Answer:
x=18
Step-by-step explanation:
180=62+(7x-8)
solve
x=18
Answer:
Step-by-step explanation:
x=2119
<u>Part 1</u>
By the inscribed angle theorem, arc PA measures 62 degrees.
<u>Part 2</u>
Angles inscribed in the same arc are congruent, so angle PRA measures 31 degrees.
<u>Part 3</u>
Diameters form semicircles, and the arc of a semicircle measures 180 degrees, so arc PAR measures 180 degrees.
<u>Part 4</u>
Subtracting arc PA from arc PAR, we get arc AR measures 118 degrees.