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Ostrovityanka [42]
3 years ago
9

PlEASE ANSWER FAST!!!!!!!!!!!!

Mathematics
1 answer:
muminat3 years ago
7 0
<span>Diameter of a grain of sand = 2 x 10^{-4} 

</span><span>Diameter of the average cell in the human body = 1 x 10^{-5}
</span>
Difference of diameter of grain of sand and cell of human body

= 2 x 10^{-4} - 1 x 10^{-5}

= 2 * 10^{-4} - 1 * 10^{-5} = ( \frac{2* 10^{-4}}{10^{-5}} -  \frac{1*10^{-5}}{10^{-5}} )*10^{-5}

= (2*10^{-4-(-5)} - 1*10^{-5-(-5)})*10^{-5}

= (2*10^{-4+5}-1*10^{-5+5})*10^-5= (2*10^{1}-1*10^{0})*10^{-5}

= (2*10 - 1*1) *10^{-5} = (20 - 1)*10^{-5}

= 19 * 10^{-5}

= 19 × 10^{-5}

Hence, the diameter of a grain of sand is 19 × 10^{-5} longer than the diameter of the average cell of the human body.
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Part A: In triangle ΔABC, we have;

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Part C: The length of DB = 9

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In triangle ΔABD, we have;

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∠DAC ≅ ∠B by Congruent Parts of Congruent Triangles are Congruent

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\displaystyle \frac{\overline{DA}}{\overline{DC}}  = \frac{\overline{BD}}{\overline{DA}}

\overline{DA}^2 = \overline{DC} \times \overline{BD}

Which gives;

\overline{DA}^2 = 4 × 9 = 36

\overline{DA} = √(36) = 6

\overline{DA}<u> = 6</u>

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