Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
Answer:
1/26
Step-by-step explanation:
Total no. of tiles = 26
In each tile , a different alphabet is written.
And we need 3 tiles (in which A , B & C are written in it) in one try.
So the probability of choosing tiles with letters A , B & C ( in one try ) = 1/26
Answer:
y=2/3x+1
Step-by-step explanation:
using the slope intercept formula, y=mx+b, where m is the slope, and b is the y intercept. So we get the equation y=2/3x+b, because the slope is given, then you use the given point and substitute it into the equation, 5=2/3(6)+b which you can solve and you will get 5=4+b, b =1, then you add 1 to your original equation to get your answer, y=2/3x+1
Answer:
95%
Step-by-step explanation:
0.6 of 40 is 24, she bought 24 green balloons.
24 × 1.5 = 36, she bought 36 yellow balloons.
So we have
40 red
24 green
36 yellow
Then from the rest of the information, 2 red, 2 green, and 1 yellow balloon all popped.
We now have
38 red
22 green
35 yellow
for a total of:
95 balloons out of 100 original balloons, 95%
