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OlgaM077 [116]
3 years ago
13

a. For what values of x does f (x )equals 3 x plus 3 sine x have a horizontal tangent​ line? b. For what values of x does f (x )

equals 3 x plus 3 sine x have a slope of 3​?
Mathematics
1 answer:
laila [671]3 years ago
5 0

Answer:

(a)Therefore the value of x=\pi

(b) Therefore the value of x =\frac{\pi}{2}

Step-by-step explanation:

Horizontal tangent line: The first order derivative of a function gives the slope of the tangent of the function. The slope of horizontal line is zero.If the slope of tangent line is zero then the tangent line is called horizontal tangent line.

(a)

Given function is,

f(x)= 3x+3sin x

Differential with respect to x

f'(x)=3+3cos x

For horizontal tangent line, f'(x)=0

3+ 3 cos x= 0

⇒3 cos x=-3

⇒cos x=-1

⇒x = 180° =\pi

Therefore the value of x=\pi

(b)

Given that, the slope is 3.

Then,f'(x)=3

3+ 3 cos x= 3

⇒3 cos x= 3-3

⇒cos x=0

⇒x = 90° =\frac{\pi}{2}

Therefore the value of x =\frac{\pi}{2}

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A company sells boxes of small blue pom-poms (b) for $42 and boxes of large orange pom-poms (p) for $52. They make batches of sm
Strike441 [17]

Answer:

b = 40 - p

42b + 52p = 350

Step-by-step explanation:

Given : No. of small blue pom-pom boxes = b

            No. of large orange pom-poms    = p

           cost of 1 box of blue pom pom = $42

           cost of one  large orange pom-pom box = $52

Solution:

Since we are given that the company has only 40 boxes

⇒b+p=40

⇒b=40-p

Since cost of 1 box of blue pom pom = $42

So, cost of b box of blue pom pom = $42b

Since,cost of one  large orange pom-pom box = $52

So,cost of p  large orange pom-pom box = $52p

We are also given that the company plan to make $350

⇒42b+52p=350

Hence Option b is correct

b = 40 - p

42b + 52p = 350

4 0
3 years ago
Read 2 more answers
I want the answer of this . .
inessss [21]

Answer:

I believe it is 2 so X=2

5 0
3 years ago
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sasho [114]
Answer is 54^2.

since there are triangles in this one, it is easier to do this. all you have to do is make boxes in and since there are angles, outside the lines. like this picture.

the orange is 1
red and dotted is 2
blue is 3
purple is 4(a regular box which should be easy to count.

all you have to do is add up all the boxes within the boundaries.
boundary 1: 12
boundary 2: 18
boundary 3: 6
boundary 4: 36

now when the boundary has a triangle in it (1, 2, & 3) divide the number you got in half or 2.
boundary 1: 6
boundary 2: 9
boundary 3: 3

the ractangle box doesn't not get divided.
boundary 1: 6
boundary 2: 9
boundary 3: 3
boundary 4: 36

add all the numbers you got now for each boundary and that would be your area squared.

6+9+3+36=54^2

so your final answer is 54^2.

i hope this helps you.

3 0
3 years ago
What is the square root of 625
QveST [7]
De finition:\\\sqrt{a}=b\ \iff b^2=a\\=====================\\\\

625|5\\125|5\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\625=5\times5\times5\times5=5^2\times5^2\\\\\sqrt{625}=\sqrt{5^2\times5^2}=(*)\\-------------------------------\\use:\ \sqrt{a\times b}=\sqrt{a}\times\sqrt{b}\ and\ \sqrt{a^2}=a\ for\ a\geq0\\-------------------------------\\(*)=\sqrt{5^2}\times\sqrt{5^2}=5\times5=\boxed{25}

Other\ solution:\\\\\sqrt{625}=25\ because\ 25^2=25\times25=625
6 0
3 years ago
1. What is the theoretical probability that the family has two dogs or two cats?
gogolik [260]

let dogs be heads. Let cats be tails. A coin has two sides, in which you are flipping two of them. Note that there can be the possible outcomes  

h-h, h-t, t-h, t-t.  

How this affects the possibility of two dogs & two cats. Note that there are 1/2 a chance of getting those two (with the others being one of each), which means that out of 4 chances, 2 are allowed.  

2/4 = 1/2  

50% is your answer

Heads represents cats and tails represents dogs. There is two coins because we are checking the probability of two pets. You have to do the experiment to get your set of data, once you get your set of data, you will be able to divide it into the probability for cats or dogs. To change the simulation to generate data for 3 pets, simply add a new coin and category for the new pet.

Hope this helps you out!

4 0
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