Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
0.54 is your answer
0.18/0.33=0.54
so your answer is 0.54
Hope this helps
<span>1.5
In C or C++, a floating point literal is nothing more than a sequence of decimal digits with either or both an decimal point, or an exponent with optionally a type specifier. The value could be any of the following: 1.5, 1.5e0, 0.15e1, 15e-1, etc.</span>
Step-by-step explanation:
the proof is given above
