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3 years ago

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Economics and finance. some of the variables that affect the monthly payment of a new-car loan are the total amount borrowed, th

e interest rate, and the length of the loan. during the fourth quarter of 2012, the mean length of a new-car loan was 65 months, a record high according to experian. suppose the length of a new-car loan is approximately normal with standard deviation nine months. (a) what is the probability ( ±±0.0001) that a new-car loan is for at most 54 months? p(x⩽54)p(x⩽54) =

1 answer:

Valentin [98]3 years ago

6 0

Is there any answer choices?

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Which expression is equivalent to b^-2/ab^-5?<br>a) a/b^5<br>b)1/ab^5<br>c)a^3b/1<br>d)b/a

Snezhnost [94]

$\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{-n}}\implies a^{{ n}}\\\\
-------------------------------\\\\
\cfrac{b^{-2}}{ab^{-5}}\implies \cfrac{b^{-2}\cdot b^{+5}}{a}\implies \cfrac{b^{-2+5}}{a}\implies \cfrac{b^3}{a}$

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2 years ago

What is 25 divided 34

Minchanka [31]

Answer:

0.74

Step-by-step explanation:

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2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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2 years ago

Jasmine has a hair ribbon collection. She ha 33 pink ribbon which is 25% of her collection. How many ribbon are in jasmines coll

jok3333 [9.3K]

Answer:

132 ribbons

Step-by-step explanation:

33/1 = 1/4

33 × 4 = 132

3 0

3 years ago

PLEASE ANSWER THESE I RLLY NEED HELP I DONT UNDERSTAND I WILL MARK YOU AS BRAINLIEST IF YOU ANSWRR CORRECTLY PLS AND TY

faust18 [17]

Answer:

Step-by-step explanation:

5. You are asked to write an equation of the line in slope-intercept form, so you need to determine the slope of the line and the y-intercept.

You're lucky. One of the points, (0,1), has an x-coordinate of 0, so you know that the y-intercept is 1.

Use the coordinates of the points to determine the slope of the line.

slope = (difference in y-coordinates)/(difference in x-coordinates) = (10-1)/(3-0) = 9/3 = 3

The slope-intercept equation of the line is y = 3x+1

:::::

7. When x = 0, function A = 0 and function B = 3, so function B has a greater initial value.

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2 years ago