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3 years ago

1. 237 + 496 = 1. 600 - 321 = 7. 993 - 294 =

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

3 0

Answer:

237+496= 733

600-321= 279

993-294= 699

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viktelen [127]

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3 years ago

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LenaWriter [7]

Answer:

5/8 = 0.625 and 62.5%

11/12 = 0.917 and 91.67%

1/4 = 0.25 and 25%

3/5 = 0.6 and 60%

Step-by-step explanation:

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3 years ago

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Stels [109]

Answer:

13. c,

14. a.

Step-by-step explanation:

13. The length of a side PQ with coordinates of

P as (x,y) and Q as (w,z)

is: $\sqrt{(x-w)^{2} +(y-z)^{2} }$

so, the length of the side AB =

$\sqrt{(5-5)^{2}+(-2+7)^{2} } =\sqrt{0^{2}+5^{2} } =5$

the length of side BC =

$\sqrt{(5-1)^{2}+(-7+2)^{2} } =\sqrt{(4)^{2}+(-5)^{2} } =\sqrt{4^{2}+5^{2} }$

the length of side AC=

$\sqrt{(5-1)^{2} +(-2+2)^{2} } =\sqrt{4^{2} } =4$

now, the easiest one will be when the vertices are on the coordinate axes.

so, option c will be the most appropriate one.

14. If u see the figure clearly, the lines l and FH are parallel.

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3 years ago

An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h

LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

$\frac{11}{1+\sqrt{2} } = a^2$

a² = $\frac{11}{2.42}$

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = $2(1+\sqrt{2} ) X (a)^2 X h$

$V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3$

Therefore, the pool can hold 65.84 ft³ of water

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3 years ago

Which equation best represents the relationship between x and y.

Assoli18 [71]

Answer:

Step-by-step explanation:

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3 years ago

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