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Svetradugi [14.3K]
3 years ago
6

8. Find the slope-intercept form for the equation of the

Mathematics
1 answer:
sashaice [31]3 years ago
6 0

Answer:

y=\frac{1}{9}x

Step-by-step explanation:

We are given that the lines passes trough the points (-9, -1) and (0,0).

(0,0) is the origin.

Slope is: m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{0-(-1)}{0-(-9)} =\boxed{\frac{1}{9}}

The slope is one-ninth.

Since the lines passes at the origin, it's y-intercept is 'zero'. We do not write zeros in slope-intercept equations, to the equation of the line should be:

y=\frac{1}{9}x

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
I’m stuck and I would really like your help.
Neporo4naja [7]

Answer:

Answer: 1/12

Step-by-step explanation:

2/5x-4=8-3/5x.

We want to tank x out of the denominator by multiplying x on both sides.

2/5-4x=8x-3/5

Now we simplify

-12x=-1

x=1/12

Put x in the equation to check it

6 0
2 years ago
Read 2 more answers
Which number has a 3 that 10 times greater than the 3 in 513?
cestrela7 [59]

The 3 in "513" is only 3. it's 1, 2, 3. If we do 3 x 10 it's 30

3 0
3 years ago
I need someone to explain on how to do this problem.​
weqwewe [10]

Answer:

I think it's x=-12 for the buttom one

Step-by-step explanation:

I think when you get open equations like these you would asume 1 is there so rewrite it as 2x + 25 = 1

so take the 25 away from 1. to do that we need to do the opisite of +

2x + 25 = 1

1 - 25 = -24

rewrite

2x = -24

take the 2 away. oppisite of mulitplication is division. so divide 2 by -24

-24 divided by 2 = -12

Hope this helps! Please mark as brainliest! Thanks! If you need me to solve the top one too, I'll do it! Just comment bellow. :D

5 0
3 years ago
Read 2 more answers
Use elimination to solve the system of equations given by 3x+ 4y= 5 and 21x+ 28y= 35.
neonofarm [45]

Answer:

(5/4-3/4)

divide both sides by -7 then line them up and solve the equation and delete one variable.

3 0
3 years ago
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