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gladu [14]
4 years ago
13

Find the domain of the function algebraically q(r)=3square root r^2 -16

Mathematics
1 answer:
lawyer [7]4 years ago
4 0
Hello : 
q(r)=3<span>√(r²-16)
q  exist : r² - 16 </span><span>≥ 0
r² </span><span>≥ 16
</span>√r² ≥ √16
but :  √16 = 4    and  √r² = <span>|r |
</span>|r | ≥ 4
r ≤ 4 or  r  ≥ 4 
the domain is :  ] -∞, 4] ∪  [,4 , + ∞ [

 
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Step-by-step explanation:

3 0
3 years ago
System of equations
nalin [4]

Answer:

The solution of the system of equations is the point (-3,0)

Step-by-step explanation:

we have

-3x+y=9 -----> equation A

2x-y=-6 -----> equation B

Adds equation A and equation B

-3x+y=9\\2x-y=-6\\------\\-3x+2x=9-6\\-x=3\\x=-3

Find the value of y

-3(-3)+y=9

9+y=9

y=9-9=0

The solution of the system of equations is the point (-3,0)

4 0
3 years ago
Which table represents a linear function?​
amid [387]
Top, right because the numbers are increasing by the same amount (2 in this case).
5 0
3 years ago
I’ll make you brainlist thankss
dusya [7]

Answer:

The equation of the line will be:

  • y = 0

Step-by-step explanation:

Given the points

  • (0, 0)
  • (3, 0)

Finding the slope

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(0,\:0\right),\:\left(x_2,\:y_2\right)=\left(3,\:0\right)

m=\frac{0-0}{3-0}

m=0

We know that the value of y-intercept can be obtained by setting x=0, and solving for y

Here,

at x = 0, the value of y = 0

Thus,

y-intercept = b = 0

We know the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept

now substituting m = 0 and b = 0 in the slope-intercept form

y = mx+b

y = 0(x) + (0)

y = 0+0

y = 0

Therefore, the equation of line will be:

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8 0
3 years ago
Which pairs of points would result in a line with a rate of change of 2:1? Select all that apply.
Helen [10]

Answer:

Options A, C, D are true.

Step-by-step explanation:

We have to choose the pair of points from that given in the attached file which will result in a line with a rate of change i.e. slope of 2:1 i.e. 2.

A. The points are (-4,-11) and (-2,-7).

Then the slope of the joining line is \frac{-7-(-11)}{-2-(-4)} =2

B. The points are (5,6) and (-5,12).

Then the slope of the joining line is \frac{12-6}{-5-5} =-\frac{3}{5}

C. The points are (0,-3) and (-4,-11).

Then the slope of the joining line is \frac{-11-(-3)}{-4-0} =2

D. The points are (0,-3) and (5,7).

Then the slope of the joining line is \frac{7-(-3)}{5-0} =2

Therefore, options A, C, D are true. (Answer)

7 0
3 years ago
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