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Yakvenalex [24]
3 years ago
6

The sum of 3 consecutive integers is 72 find the integers

Mathematics
2 answers:
mote1985 [20]3 years ago
7 0
Consecutive integers are numbers that follow after each other. So 1,2,3,4,5 are consecutive integers

We need 3 consecutive integers that is 72. Note the word is means =

We can set this up like the following: 
x  + (x + 1) + (x+2) = 72
Now combine like terms
x +x + x = 3x
1 + 2  =  3

3x + 3 = 72
Solve for x
3x + 6 = 72
3x = 72 - 3
3x = 69
3x / 3 = 69 / 3
x = 23


Now that we have solved for the first x, which is 23, we plug this into (x + 1) and (x + 2) to solve the other numbers we need

x + (x + 1) + (x + 2) = 72

(x + 1) = (23 + 1) = 24
(x + 2) = (23 + 2) = 25


So we have the following:

x = 23
(x + 1) = (23 + 1) = 24
(x + 2) = (23 + 2) = 25

Our answers are 23, 24, 25, which are consecutive number and when you add them, they = 72
Elis [28]3 years ago
5 0
-----------------------------------------
Define x :
-----------------------------------------
Let the smallest number be x.
The other two numbers will be x + 1 and x + 2.

-----------------------------------------
Construct Equation :
-----------------------------------------
Sum of these numbers is 72
⇒ x + x + 1 + x + 2 = 72

-----------------------------------------
Solve for x :
-----------------------------------------
x + x + 1 + x + 2 = 72
3x + 3 = 72
3x = 69
x = 23

-----------------------------------------
Find the numbers :
-----------------------------------------
1st number = x = 23
2nd number = x + 1 = 23 + 1 = 24
3rd number = x + 2 = 23 + 2 = 25

----------------------------------------------------------------------------------
Answer : The numbers are 23, 24 and 25.
----------------------------------------------------------------------------------
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Can someone help me out with this? I’m not sure what I’m doing wrong.
Nadusha1986 [10]

Answer:


Step-by-step explanation:

This is a system of inequalities such that:

\left \{ {{2x+3y\geq 2} \atop {3x-4y\leq 3}} \right.

Let's start by solving for y for both equations:

Equation 1:

2x+3y\geq  2\\\\3y\geq -2x+2\\\\y \geq \frac{-2x+2}{3}

Equation 2:

3x-4y\leq 3\\\\-4y\leq -3x+3\\\\y\geq -\frac{(-3x+3)}{4}


Now if we substitute the 2nd y into the first equation we obtain:

2x+3(\frac{3x-3}{4}) \geq  2\\\\2x+\frac{9x-9}{4}\geq 2\\\\\frac{8x+9x-9}{4}\geq 2\\\\17x-9\geq 8\\\\17x\geq 17\\\\x\geq 1


Now we will solve for the second equation using the first result of y and we obtain:

3x-4(\frac{-2x+2}{3}\leq 3\\\\3x+\frac{8x-8}{3}\leq 3\\\\\frac{9x+8x-8}{3}\leq 3\\\\17x-8\leq 9\\\\17x\leq 17\\\\x\leq 1

And so our solution for the system of equations is:

x \leq 1\\and \\y\geq \frac{-2x+2}{3}

As well as:

x>1\\and\\y\geq \frac{3x-3}{4}


4 0
4 years ago
Yes,I need help with another one of these , the number that got cut off is 24 btw.
V125BC [204]

Since, PS and QR are parallel, we know that <QRP is equal to <RPS.  Therefore, we can solve for y by setting the two equations equal to each other.

5y+14=8y-13

<em>*Subtract 5y from both sides to isolate the variable*</em>

14=3y-13

<em>*Add 13 to both sides*</em>

27=3y

<em>*Divide both sides by 3*</em>

9=y


Now, plug in 9 for y in the equation 8y-13 to find the measure of that angle.

8(9)-13

<RPS=59


Now, the sum of the angles in any triangle is equal to 180 degrees.  We can use this knowledge to set up an equation to solve for x.

3x+2x+1+59=180

<em>*Combine like terms*</em>

5x+60=180

<em>*Subtract 60 from both sides*</em>

5x=120

<em>*Divide both sides by 5*</em>

x=24


Now, we can find <RSP by pluggin 24 in for x.

2(24)+1

48+1

<RSP=49 degrees


Hope this helps!!

3 0
3 years ago
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Ganezh [65]

Answer:a

Step-by-step explanation:

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