All categories

4 years ago

suppose you were in space in a weightless environment, would it require force to put an object in motion

2 answers:

7 0

<span>Yes. Even though the object may be "weightless" it still has mass. Inertia is a property of matter (or mass) that resists changes in motion. They object will indeed require a force to set it in motion because of it's Inertia.

</span>

Ivanshal [37]4 years ago

7 0

Yes because the object has mass, therefore you need force.

You might be interested in

A basketball player shoots toward a basket 4.9 m away and 3.0 m above the floor. If the ball is released 1.8 m above the floor a

Zolol [24]

Answer:

v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

x = v₀ₓ t

y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

the time to reach the basket is

t = x / v₀ₓ

we substitute

y- y₀ = $\frac{ v_o \ x \ sin \theta }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }$

y - y₀ = x tan θ - $\frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }$

we substitute the values

3 -1.8 = 3.0 tan 60 - $\frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}$

1.2 = 5.196 - 176.4 1 / v₀²

176.4 1 / v₀² = 3.996

v₀ = $\sqrt{ \frac{ 176.4}{3.996} }$

v₀ = 6.64 m / s

6 0

3 years ago

Superman is off to visit Lois lane. He sees he's late and increases his flying speed. I know he defies the laws of physics anywa

mario62 [17]

Answer:

975 m/s^2

Explanation:

The formula for rate of acceleration is

(Final velocity - intial velocity)/ time taken

If you plug in your data you will get 975 m/s^2

(1600 m/s -1210 m/s )/.4 s = 975 m^2

7 0

3 years ago

GIVING EASY BRAINLIEST PLEASE HELP!!

AlekseyPX

Answer: I think the answer is heat flows from the lemonade to the ice

Explanation: the heat transports to the lemonade which makes the lemonade hot and the ice will melt if the drink is hot

7 0

3 years ago

From Gauss's law, the electric field set up by a uniform line of charge is given by the following expression where is a unit vec

Evgesh-ka [11]

Answer:

$\Delta V=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})$

Explanation:

Using the Gauss Law, we obtain the electric Field for a uniform large line of charge:

$2\pi r L*E=\lambda *L/\epsilon_{o}$

$E=\lambda /\(2 \pi* r *\epsilon_{o})$

We calculate the potential difference from the electric field:

$\Delta V=-\int\limits^{r_{1}}_{r_{2}} E \, dr =-\int\limits^{r_{1}}_{r_{2}} \lambda dr/ (2\pi*r*\epsilon_{o})=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})$

5 0

4 years ago

Explain the versatility of epithelial tissue

Dafna11 [192]

Epithelial cells are classified by the following three factors : 1. Shape . 2. Stratification. 3.Specialization . It's a main aspect to the mehe family , and plays a huge part in helping the movement of bobbing your head.

8 0

3 years ago

Read 2 more answers