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3 years ago

13

Which answer explains why plate B is moving underneath plate A

1 answer:

blsea [12.9K]3 years ago

4 0

Answer:

A.

Explanation:

Earth is composed of different layers and one layer moves over another due to differences in the densities.

According to the physics of density, a substance having less density floats over a higher density substance. The oceanic crust has more density than the continental crust that is why continental crust float over oceanic crust.

So in the given example, plate B is moving below the plate A, it means plate B is more dense than plate A because plate B is composed of oceanic crust . <u>For example : continents float over the asthenosphere (a layer below the lithosphere).</u>

Hence, the correct answer is "A ".

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Marta_Voda [28]

Answer:

-6 m/s^2

Explanation:

30 - 90 = -60

-60 / 10 = -6

If acceleration was constant, it will be -6 m/s^2

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2 years ago

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Mama L [17]

The acceleration of the charge is 1.07 × 10²⁸ m/s². It is obtained as the force per unit mass of the charge.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The electric force is found as;

$\rm F = \frac{Kq_1q_2}{r^2} \\\\ F= \frac{9 \times 10^9 \times( 3.2 \times 10^{-19})^2}{(3.60 \times 10^{-15})^2}\\\\ F=71.1 \ N$

The acceleration of the charge is found as;

$\rm a = \frac{F}{m} \\\\ \rm a = \frac{71.1}{4.0026 \TIMES 1.66 \TIMES 10^{-27}} \\\\ a=1.07 \times 10^{28} \ m/s^2$

Hence,the acceleration of the charge is 1.07 × 10²⁸ m/s².

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2 years ago

A bicycle has wheels of 0.8 m diameter. The bicyclist accelerates from rest with constant acceleration to 22 km/h in 11.6 s. Wha

larisa [96]

Answer:

α = 1.32 rad/s²

Explanation:

given,

diameter of the bicycle = 0.8 m

radius of the bicycle = 0.4 m

initial speed of the bicyclist,u = 0 m/s

final speed of the bicyclist,v = 22 Km/h = 22 x 0.278

= 6.12 m/s

time,t = 11.6 s

acceleration = $\dfrac{v-u}{t}$

= $\dfrac{6.12-0}{11.6}$

=0.53 m/s²

we know,

a = α r

$\alpha=\dfrac{a}{r}$

$\alpha=\dfrac{0.53}{0.4}$

α = 1.32 rad/s²

the angular acceleration of the wheels is equal to α = 1.32 rad/s²

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3 years ago

A dentist’s drill starts from rest. After 3.20 s of constant angu-lar acceleration, it turns at a rate of 2.51 3 104 re v/m i n.

Gekata [30.6K]

Answer:

$ΔTita = 4205.6 rad$

Explanation:

$w_{i}$ means initial angular velocity, which is 0 rev/min

$w_{f}$ means final angular velocity, which is $2.513*10^{4}rev/min$

t means time t= 3.20 s

one revolution is equivalent to 2πrad so the final angular velocity is:

$w_{f}$ = (2π/60) *2.513*10^{4} rad/s

$w_{f}$ = 2628.5 rad/s

so the angular acceleration, α will be:

α = 2628.5 rad/s / 3.20 s

$a = 821.40 rad/s^{2}$

so the rotational motion about a fixed axis is:

$w^{2} _{f} =w^{2} _{i}$ + 2αΔTita where ΔTita is the angle in radians

so now find the ΔTita the subject of the formula

ΔTita = $\frac{w^{2} _{f}-w^{2} _{i} }{2a}$

$ΔTita = ((2628.5)^{2} - (0 rev/min)^{2}) / 2* 821.40$

$ΔTita = 4205.6 rad$

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Lynna [10]

Answer:

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Explanation:

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