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NNADVOKAT [17]
3 years ago
8

An object is dropped from a height of 25 meters. At what velocity will it hit the ground?

Physics
1 answer:
Goryan [66]3 years ago
6 0
You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing
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A constant net force of 20 N is applied to a 32kg car, causing it to speed up from 4.0 to 9.0 m/s. How long is the force applied
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Answer:

8 seconds

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v = final velocity

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20t = 32 * 5

t = 32 * 5/ 20

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uranmaximum [27]

Answer:

<em>a) 105935.7 Pa</em>

<em>b) 103630.35 Pa</em>

Explanation:

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We have to find the height of the tank

From the equation for finding the volume of the cylinder,

V = \pi r^2h

where

V is the volume of the cylinder

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substituting values, we have

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Pressure at the bottom of the tank P = ρgh

where

ρ is the density of water = 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

h is the depth of water which is equal to the height of the tank

substituting values, we have

P = 1000 x 9.81 x 0.47 = 4610.7 Pa

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2 years ago
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Galina-37 [17]

Answer:

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