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NNADVOKAT [17]
3 years ago
8

An object is dropped from a height of 25 meters. At what velocity will it hit the ground?

Physics
1 answer:
Goryan [66]3 years ago
6 0
You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing
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A toy train is traveling along a circular track
Molodets [167]

Answer:

0.25 m

Explanation:

a = v² / r

4.0 m/s² = (1.0 m/s)² / r

r = 0.25 m

3 0
3 years ago
Two identical mandolin strings under 200 N of tension are sounding tones with frequencies of 590 Hz. The peg of one string slips
Slav-nsk [51]

To solve this problem it is necessary to apply the concepts related to frequency and vibration of strings. Mathematically the frequency can be expressed as

f = \frac{v}{\lambda}

Then the relation between two different frequencies with same wavelength would be

\frac{f'}{f} = \frac{v'/\wavelength}{v/\wavelength}

\frac{f'}{f} = \frac{v'}{v}

The beat frequency heard when the two strings are sounded simultaneously is

f_{beat} = f-f'

f_{beat} = f(1-\frac{f'}{f})

f_{beat} = f(1-\frac{v'}{v})

We have the velocity of the transverse waves in stretched string as

v = \sqrt{\frac{T}{\mu}}

v = \sqrt{\frac{200N}{\mu}}

And,

v' = \sqrt{\frac{196N}{\mu}}

Therefore the relation between the two is,

\frac{v'}{v} = \sqrt{\frac{192}{200}}

\frac{v'}{v} = \sqrt{0.96}

Finally substituting this value at the frequency beat equation we have

f_{beat} = 590(1-\sqrt{0-96})

f_{beat} = 11.92Hz

Therefore the beats per second are 11.92Hz

4 0
3 years ago
Why are images reflected from a rough surface not as clear as those reflected from a smooth
ioda

Answer:

Just as images are reflected from the surface of a mirror, light reflected from a smooth water surface also produced a clear image. ... Consequently, the outgoing rays are reflected at many different angles and the image is disrupted. Reflection from such a rough surface is called diffuse reflection and appears matte.

Explanation:

hi po I hope it's help you

7 0
3 years ago
an experiment is set up to measure the effect of a gasoline additive on fuel consumption rate. what would be the control in this
Tamiku [17]
The control setup in this experiment would be one tank that does not contain any of the additives. Since the tanks with the gasoline additives would need to be compared with a tank that is not affected by the results of these additives.
4 0
3 years ago
Explain the difference between evaporation and boiling
azamat
Well evaporation<span> is a gradual vaporization of a liquid on the surface whereas </span>boiling<span> is a rapid vaporization of a liquid only when it is heated to its </span>boiling<span> point. </span>
7 0
3 years ago
Read 2 more answers
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