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3 years ago

SOMEBODY BETTER ANSWER THIS QUESTION OR IMA MAKE YOU EAT MY TOE :)

Mathematics

1 answer:

harina [27]3 years ago

5 0

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How do we multiply fractions w whole numbers

Art [367]

You convert the whole number into a fraction by adding a one underneath it, after that you multiply across.

6 0

3 years ago

Read 2 more answers

56 is 0.4% of what number?

kvv77 [185]

Answer:

140

Step-by-step explanation:

Let the number = x

Hence, the expression can be written has:

0.4 of x = 56

0.4x = 56

Divide both sides by 0.4

0.4x / 0.4 = 56 / 0.4

x = 140

Hence, 56 is 0.4 of 140

8 0

3 years ago

Use algebraic rules of equations to predict the solution type to the system of equations. Include all of your work for full cred

quester [9]

Yea I’m sorry I hope you find it doe!

3 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

Find the area of a triangle whose base is 10 mm, and its height is 15 mm.

hjlf

Answer:

75mm²

Step-by-step explanation:

Area of a triangle

1/2 × base × height

= 1/2 × 10mm × 15mm

= 75mm²

5 0

3 years ago