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deff fn [24]
4 years ago
5

Emily thinks that -11/6 - (-2/3) is -5/2. Identify the error ghat emily made. Then correct Emily’s error and find the correct va

lue.
Mathematics
1 answer:
Amanda [17]4 years ago
7 0
\bf \stackrel{\textit{she subtracted }\frac{2}{3}\textit{ instead of adding it}}{-\cfrac{11}{6}-\left(\cfrac{2}{3}  \right)\impliedby \stackrel{LCD}{6}\implies \cfrac{-(1)11~~-~~(2)2}{6}}\implies \cfrac{-11~~-~~4}{6}
\\\\\\
\cfrac{-15}{6}\implies \stackrel{simplified}{-\cfrac{5}{2}}\impliedby \textit{that's correct, assuming is }\frac{2}{3}~~but~is~~-\frac{2}{3}\\\\
-------------------------------

\bf \stackrel{\textit{recall that minus times minus is plus}}{-\cfrac{11}{6}-\left(-\cfrac{2}{3}  \right)\implies -\cfrac{11}{6}+\cfrac{2}{3}}\implies \cfrac{-(1)11+(2)2}{6}
\\\\\\
\cfrac{-11+4}{6}\implies -\cfrac{7}{6}\quad \checkmark
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PLS HURRY Point S is translated 5 units to the left and 12 units up to create point S'. Find the distance between point S and po
svet-max [94.6K]

Given:

Point S is translated 5 units to the left and 12 units up to create point S'.

To find:

The distance between the points S and S'.

Solution:

Point S is translated 5 units to the left and 12 units up to create point S'.

The diagram for the given problem is shown below.

From the below figure it is clear that the distance between the point S and S' is the height of a right triangle whose legs are 5 units and 12 units.

By Pythagoras theorem,

Hypotenuse^2=Perpendicular^2+Base^2

SS'^2=(12)^2+(5)^2

SS'^2=144+25

SS'^2=169

Taking square root on both sides.

SS'=\sqrt{169}

SS'=13

Therefore, the distance between S and S' is 13 units.

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