Answer:
D(4,-3)
Step-by-step explanation:
Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)
Let the coordinate of the fourth vertex be D(x,y).
We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.
The diagonals are BD and AC
Midpoint of BD = Midpoint of AC
The coordinates of the fourth vertex is D(4,-3)
Answer:
c ≈ 0.00782852
, 3.99906481
Step-by-step explanation:
Answer:
1/15
Step-by-step explanation:
-1/3 -(-3/5)
-1/3 + 3/5
(-1 × 5) / (3 × 5) + (3 × 3) / (5 × 3)
-5 / 15 + 6 / 15 = 1/15
64 + 43 = 107
107 - 43 = 64
107 - 64 = 43
the solutions to a general quadratic equation is
X=-b±√b²-4ac/2a ,, When ax²+bx+c=0
the discriminant is the expression under the radical b²−4ac
Part A:
discriminant is (-16)² - 4(9)(60) = -1904
there are two complex solutions
Part B:
4x² + 8x − 5 = 0
4x² + 10x -2x - 5=0
2x ( 2x + 5) - 1(2 x + 5) =0
(2x + 5)(2x-1) = 0
/ \
/ \
2x+5 = 0 2x-1 =0
x = -5/2 x = 1/2
