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3 years ago

15

She decides that as long the length rounds to 3.2 inches. It will work. She has several pieces of wood to choose from. which of

the pieces of wood below can she use for her project

1 answer:

juin [17]3 years ago

7 0

Anyone that is 3.2 inches

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Daredevil Danny takes a practice jump as shown on the graph below. Complete the steps to determine the equation for the paraboli

Tju [1.3M]

Answer:

Step 2:

Part A

f(x) = a(x-h)^2 +k

Part B

I'm not really sure about this part

Part C

f(x)=-12/25(x-25)^2+32

Step 3:

Part A

y = ax^2 + bx + c

Part B

f(x) = -12/25(x - 25)^2 + 32

Part C

a = -12/25

b = 0

c = 32

Step-by-step explanation:

Hope This Helps!

Sorry For Taking So Long!

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3 years ago

Which of the following is true for an isometry?

FrozenT [24]

Isometry is defined as the <span> transformation that is invariant with respect to the distance
The statement that is true for isometry that is corrrect is
</span><span>The preimage and the image are congruent.
</span>so correct option is A as both the preimage and image are congruent
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3 years ago

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Nataly_w [17]

The answer would be A

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2 years ago

Read 2 more answers

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

So

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

So

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

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3 years ago

Patrycja goes shopping in a supermarket.

inysia [295]

Answer:£0.37

Step-by-step explanation:

£4.44/12=£0.37

3 0

2 years ago