Answer:
C
Step-by-step explanation:
can I be brainliest?
Slope=(y2-y1)/(x2-x1)
=(5-4)/(4-2)
=1/2
slope > 0 => the line rises (from left to right).
Answer:
A.
This assumption is that the distribution of polyunsaturated fat % of each if these four regimes must be with equal variances as well as uniform.
B.
The null hypothesis
H0: μ1 = μ2 = μ3 = μ4
The alternate hypothesis:
H1: at least 2 means are unequal
C.
First we calculate the grand mean
= 1/54[15(42.9)+17(43.1)+8(43.7)+14(43.9)]
= (643.5 +732.7 + 349.6 + 614.6)/54
= 2340.4/54
= 43.341
Sum of squared treatment
= [15(42.9-43.341)²+17(43.1-43.341)²+8(43.7-43.341)²+14(43.9-43.341)²]
= 9.3104
Mean square of treatment
= SST/I-1
= 9.3104/4-1
= 9.3104/3
= 3.1035
Error sum of squared
= (15-1)*(1.3)² + (17-1)*(1.5)² + (8-1)*(1.2)² + (14-1)*(1.2)²
= 88.46
Error mean square
MSE = 88.46/54-4
= 1.7692
Test statistic
= 3.1035/1.7692
= 1.75
Is there supposed to be a graph or a “circle”? you kinda need it to solve the problem lol
If a vertical line crosses the relation on the graph only once in all locations, the relation is <span>a </span>function. If<span> a vertical line crosses the relation more than once, the relation is </span>not a function<span>. So number 18 is not a function but number 19 is a function.
Hope this helps!!</span>
