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Citrus2011 [14]
3 years ago
15

-5.2k+2.9 =-12k+30.1Please show work !

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0

answer: 3.8857

explanation:

Simplifying

-5k + 2.9 = -12k + 30.1

Reorder the terms:

2.9 + -5k = -12k + 30.1

Reorder the terms:

2.9 + -5k = 30.1 + -12k

Solving

2.9 + -5k = 30.1 + -12k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '12k' to each side of the equation.

2.9 + -5k + 12k = 30.1 + -12k + 12k

Combine like terms: -5k + 12k = 7k

2.9 + 7k = 30.1 + -12k + 12k

Combine like terms: -12k + 12k = 0

2.9 + 7k = 30.1 + 0

2.9 + 7k = 30.1

Add '-2.9' to each side of the equation.

2.9 + -2.9 + 7k = 30.1 + -2.9

Combine like terms: 2.9 + -2.9 = 0.0

0.0 + 7k = 30.1 + -2.9

7k = 30.1 + -2.9

Combine like terms: 30.1 + -2.9 = 27.2

7k = 27.2

Divide each side by '7'.

k = 3.885714286

Simplifying

k = 3.885714286

hope this helped;))))

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PYTHAGORAS THEROM AND TRIGONOMETRY RATIO​
marysya [2.9K]

Answer:

1) ΔACD is a right triangle at C

=> sin 32° = AC/15

⇔ AC = sin 32°.15 ≈ 7.9 (cm)

2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:

AB² = AC² + BC²

⇔ AB² = 7.9² + 9.7² = 156.5

⇒ AB = 12.5 (cm)

3)  ΔABC is a right triangle at C

=> sin ∠BAC = BC/AB

⇔ sin ∠BAC = 9.7/12.5 = 0.776

⇒ ∠BAC ≈ 50.9°

4) ΔACD is a right triangle at C

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Step-by-step explanation:

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2 years ago
72 greater than a is at least 7
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The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the
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Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

P(X > x) = \frac{b - x}{b - a}

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This means that a = 0.95, b = 1.05

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

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So

\frac{1.05 - x}{1.05 - 0.95} = 0.9

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x = 1.05 - 0.9*0.1

x = 0.96

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

4 0
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