All categories

2 years ago

1/2x-2/3>3 enter your answer using interval notation

Mathematics

1 answer:

Nata [24]2 years ago

7 0

So basically u keep the x on one side and the rest on the other. Get a common denominator. to get rid of the half u times both sides by 2.
hope this helps

You might be interested in

A bag contains 12 toffees. Kate eats 3 toffees and Josh eats 4 toffees.

Vinvika [58]

Answer:

5/12

Step-by-step explanation:

3 + 5 = 7

12/12 - 7/12 = 5/12

4 0

1 year ago

Read 2 more answers

Simplify each of the expressions. (6y^2 + 4y + 5) – (3 – 7y + y^2)

Ludmilka [50]

(6y^2 + 4y + 5) – (3 – 7y + y^2)
= 6y^2 + 4y + 5 – 3 + 7y - y^2
= 5y^2 + 11y + 2

hope it helps

8 0

2 years ago

Read 2 more answers

HELP will give branliest!

amm1812

Answer:

perimeter 140

Step-by-step explanation:

60L x 10W = 600

60(2) + 10(2) = 140

8 0

2 years ago

Evaluate the given expression if a = 2 and b = -4 a2-b3

IceJOKER [234]

Answer:

Step-by-step explanation:

${a}^{2} - {b}^{3} \\ \\ = {(2)}^{2} - {( - 3)}^{3} \\ \\ = 4 - ( - 27) \\ \\ = 4 + 27 \\ \\ = 31$

5 0

3 years ago

Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago