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valentinak56 [21]
3 years ago
11

Sarah solved a quadratic equation. Her work is shown below, with Step 1 missing.

Mathematics
2 answers:
malfutka [58]3 years ago
7 0

she Could have wriiten  2(9+1)^2+6+134  did that help!!!!!!!!!??????????

to check maybe u should try it jsut caculate it  :D

KengaRu [80]3 years ago
3 0

Answer:

step 1 - subtract 6 from both sides

Step-by-step explanation:

Given

2(x + 1)² + 6 = 134

Step 1 - subtract 6 from both sides

2(x + 1)² = 128

Step 2 - divide both sides by 2

(x + 1)² = 64

Step 3 - take the square root of both sides

x + 1 = ± \sqrt{64} = ± 8

Step 4 - subtract 1 from both side

x = - 1 ± 8

Step 5 - solve for x

x = - 1 - 8 = - 9 or x = - 1 + 8 = 7

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Lisa had $4.26 in her purse she bought some school supplies for $2.75 how much money does Lisa have left
son4ous [18]

Answer:

$1.51

Step-by-step explanation:

To find how much money Lisa has left, subtract the money she spent from how much money she started with.

4.26 - 2.75=1.51

Therefore, Lisa has $1.51 left.

3 0
3 years ago
A farmer planted 3 types of trees on 22 acres of land. He planted 48 trees per acre. What is the total of trees the farmer plant
antoniya [11.8K]
Hey there! :D

He planted 48 trees per acre. Ignore the '3 types of trees' part. I think the question is trying to confuse you. Multiply 48 by 22.

48*22= 1056

The farmer has planted 1056 trees.

I hope this helps!
~kaikers 
7 0
4 years ago
Read 2 more answers
How do you simplify and multiply 2/5×6/7
DiKsa [7]
2/5 x 6/7
Multiply the numerator and denominator
2 times 6
5 times 7=
12/35
You can't simplify it

7 0
4 years ago
Read 2 more answers
HELPPPPPPPPPPPPPPPPPPPPPPPPP
Over [174]

Answer:

1: 11b(exponent of 2) +6b -9c

2: -11xy -9x -5x(exponent of 2)y

Step-by-step explanation:

8 0
3 years ago
Show the processes for solving 2x+3y=5 and 4x - y=17 using elimination and substitution
r-ruslan [8.4K]

<u>ANSWER:  </u>

The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).

<u>SOLUTION: </u>

Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).

Let us first solve the above equations using <em>elimination process. </em>

For elimination, one of the coefficients of variables has to be same in order to cancel them.

Now solve (1) and (2)

eqn (1) \times 2 → 4x + 6y = 10

eqn (2) → 4x – y = 17

(-) ----------------------------

     0x + 7y = -7

y = -1

Substitute y value in (2)

4 x-(-1)=17 \rightarrow 4 x+1=17 \rightarrow 4 x=17-1 \rightarrow 4 x=16 \rightarrow x=4

So, solution of two equations is (4, -1).

<u><em>Now let us solve using substitution process.</em></u>

Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17

Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56  

x = 4

Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1

Hence, the solution of the two equations is (4, -1).

7 0
3 years ago
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