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3 years ago

Can someone help me out please ? I am very stuck here

Chemistry

1 answer:

Alex17521 [72]3 years ago

7 0

Hey there!

Atomic Masses :

H = 1.00794 a.m.u
N = 14.0067 a.m.u
O = 15.9994 a.m.u

Therefore:

HNO3 = 1.00794 + 14.0067 + ( 15.9994 * 3 ) => 63.0128 g/mol

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You throw a barbeque for your friends. Before you start the grill, your propane tank has a pressure of 78 psi. When you’re finis

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Answer:

b. 485 kPa

Explanation:

Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:

P1T2 = P2T1

P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas

Where P1 = 74psi

T2 = 20°C + 273.15 = 293.15K

P2 = ?

T1 = (95°F -32) * 5/9 + 273.15 = 308.15K

Replacing:

74psi*293.15K = P2*308.15K

70.4psi

In kPa:

70.4psi * (6.895kPa / 1psi) =

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2 years ago

Identifying a trend in temperature change over time

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Answer:

More than three decade the temperature of earth is increasing equally by the rate of 0.8 Celsius (1.4 Fahrenheit). It is going to be very harmful for the human being as well animals. The global warming is the main reason and hole in the ozone layer had been the cause of increasing the temperature of the earth. Humans are also involved in cause in temperature of earth by cutting forests and making land suitable for residence and not planting more trees instead of the cut trees.

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3 years ago

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Benzene and toluene form ideal solutions. Consider a solution of benzene and toluene prepared at 25∘C. As suming that the mole f

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Answer:

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2 years ago

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In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined

faltersainse [42]

Answer:

For A: The standard cell potential of the reaction is 4.4 V

For B: The standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C: The reaction is spontaneous as written.

Explanation:

For A:

The given chemical reaction follows:

$2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)$

The given half reaction follows:

Oxidation half reaction: $Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V$ ( × 2)

Reduction half reaction: $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=1.36-(-3.04)=4.4V$

Hence, the standard cell potential of the reaction is 4.4 V

For B:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

n = number of electrons transferred = $2mol\text{ e}^-$

F = Faradays constant = $96500J/V.mol\text{ e}^-$

$E^o_{cell}$ = standard cell potential = 4.4 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J$

Hence, the standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C:

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

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3 years ago

If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?

Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 412.072 \ g \ Cl_2$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

412.072 g Cl₂ ≈ 412 g Cl₂

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2 years ago