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mars1129 [50]
3 years ago
7

How many grams of lithium sulfide must be dissolved in 1600.0 g water to make a 2.0 molal solution?

Chemistry
1 answer:
klasskru [66]3 years ago
7 0
Molality is the number of moles of solutes in 1 kg of solvent.
the molality of solution to be prepared is 2.0 molal. 
therefore 2 moles in 1 kg water.
the mass of Li₂S required is - 46 g/mol x 2.0 mol = 92 g
the mass in 1 kg of solvent is - 92 g
Therefore mass of Li₂S required in 1600.0 g is - 92 g/kg x 1.6 kg = 147.2 g
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8 0
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<img src="https://tex.z-dn.net/?f=H_2PO_4%5E-%28aq%29%20%5Crightarrow%20H%5E%2B%28aq%29%20%2B%20HPO_4%5E%7B2-%7D%28aq%29" id="Te
klasskru [66]

Answer:

The pH of the buffer solution = 8.05

Explanation:

Using the Henderson - Hasselbalch equation;

pH = pKa₂ + log ( [HPO₄²-]/[H₂PO4⁻]

where pKa₂ = -log (Ka₂) = -log ( 6.1 * 10⁻⁸) = 7.21

Concentration of OH⁻ added = 0.069 M (i.e. 0.069 mol/L)

[H₂PO4⁻] after addition of OH⁻ = 0.165 - 0.069 = 0.096 M

[HPO₄²-] after addition of OH⁻ = 0.594 + 0.069 = 0.663 M

Therefore,

pH = 7.21 + log (0.663 / 0.096)

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pH = 8.05

4 0
3 years ago
What is the mass of 18.0 mL of honey if its' density is 1.42 g/mL?
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mass (m) = ? , volume = 18.0 ml , density = 1.42 g/ml .

density =  \frac{mass}{volume}  \\  \\ d =  \frac{m}{v}  \\  \\ mass = density \times volume \\  \\ m = d \times v \\  \\ m = 18 \: ml \times  \: 1.42 \:  \frac{g}{ml}  \\  \\ m = 25.56 \: g

I hope I helped you^_^

8 0
2 years ago
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